1. A brick is dropped from a high wall. a. What is its velocity after 5.0 s? b. How far does the brick fall during this time?
1 answer:
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The induced emf in the loop is -1500 μ V or - 0.0015 V .
According to the question
A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0. 50 t.
i.e
Magnetic field (B) = 0. 50 T
Area of circle or loop =
Now,
The area of the loop decreases at a rate of 3. 0 × 10⁻³ m/s
i.e
dA = 3. 0 × 10⁻³ meter²
dt = 1 sec
As per the formula of Induced e.m.f in the loop
emf is dependent on number of turns of coil, shape of the coil, strength of magnet and speed with which magnet is moved. Emf is independent of resistivity of wire of the coil.
where A is the area of the loop.
Now ,
Substituting the values in the formula
e = - 0.0015 V
OR
e = -1500 * 10⁻⁶ V
e = -1500 μ V
Negative just signifies emf will such be induced that current induced will oppose change in magnetic field though it
To know more about induced emf here:
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Answer:
6.03 m
Explanation:
First of all, let's convert the angular velocity from revolutions per minute to radians per second:
The frictional force on the block ranges from zero to a maximum value of
In order for the block to remain stuck on the turntable, the frictional force must be equal to the centripetal force, so we can write:
where
m is the mass of the block
is the angular velocity
r is the distance of the block from the centre
is the coefficient of static friction
g = 9.8 m/s^2
Solving for r, we find: