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Deffense [45]
2 years ago
12

1. A brick is dropped from a high wall. a. What is its velocity after 5.0 s? b. How far does the brick fall during this time?​

Physics
1 answer:
RSB [31]2 years ago
5 0

Answer:

(I) 49m/s

(ii) 122.5m

Explanation:

Data obtained from the question include:

Time (t) = 5 s

Acceleration due to gravity (g) = 9.8 m/s²

<h3>(A) Determination of the brick's velocity.</h3>

Time (t) = 4 s

Acceleration due to gravity (g) = 9.8 m/s²

<h3>Velocity (v) =?</h3>

v = gt

v = 5× 9.8

v = 49 m/s

Thus, the brick's velocity after 4 s is 49m/s

B. Determination of how far the brick fall in 5 s.

Time (t) = 5 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

h = ½gt²

h = ½ × 9.8 × 5²

h = 5× 16

h = 122.5 m

Thus, the brick fall 122.5m during the time.

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How much time does it take a trucker to deliver his shipment 480 km away travelling at an average speed of 120 km/hr?​
kifflom [539]

Answer: time=4 hours

Explanation:

formula:

speed = \frac{distance}{time}

time = \frac{distance}{speed}

time= x

speed = 120km/hr

distance = 480 km

x = \frac{480 km}{120km/hr\\}

=\frac{48km*hr}{12km}

cut the zeros

and remove the signs

then

\frac{48}{12} = 4

therefore, time taken to deliver the shipment by trucker is 4 hours

8 0
3 years ago
A 25.0 g marble sliding to the right at 20.0 cm/s overtakes and collides elastically with a 10.0 g marble moving in the same dir
ikadub [295]
In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,

   KE1  = KE2

The kinetic energy of the system before the collision is solved below.

  KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
  KE1 = 6125 g cm²/s²

This value should also be equal to KE2, which can be calculated using the conditions after the collision.

KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)

The value of x from the equation is 17.16 cm/s.

Hence, the answer is 17.16 cm/s. 
6 0
3 years ago
If a transformer has 50 turns in the primary winding and 10 turns on the secondary winding, what is the reflected resistance in
Elza [17]

Answer:

The reflected resistance in the primary winding is 6250 Ω

Explanation:

Given;

number of turns in the primary winding, N_P = 50 turns

number of turns in the secondary winding, N_S = 10 turns

the secondary load resistance, R_S = 250 Ω

Determine the turns ratio;

K = \frac{N_P}{N_S} \\\\K = \frac{50}{10} \\\\K = 5

Now, determine the reflected resistance in the primary winding;

\frac{R_P}{R_S} = K^2\\\\R_P = R_SK^2\\\\R_P = 250(5)^2\\\\R_P = 6250 \ Ohms

Therefore, the reflected resistance in the primary winding is 6250 Ω

6 0
3 years ago
What is the theory of light?
Lostsunrise [7]

Answer:

Corpuscular theory of light

Explanation:

In optics, the corpuscular theory of light, arguably set forward by Descartes in 1637, states that light is made up of small discrete particles called "corpuscles" which travel in a straight line with a finite velocity and possess impetus. This was based on an alternate description of atomism of the time period.

3 0
3 years ago
A 1200 kg sports car accelerates from 0 m/s to 30 m/s in 10 s. What is the average power of the engine?
DIA [1.3K]

Answer:

3600N

Explanation:

Given: m = 1200kg, Vo = 0m/s, Vf = 30m/s, Δt = 10s

ΣF = ma

we need to find 'a' first, using the definition of 'a' we get equation:

a = (Vf-Vo)/Δt

a = (30m/s)/10s

a = 3 m/s^2

now substitute into top equation

ΣF = ma

Fengine = (1200kg)(3m/s^2)

Fengine = 3600N

5 0
2 years ago
Read 2 more answers
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