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mihalych1998 [28]
3 years ago
8

*URGENT*

Chemistry
2 answers:
Ksivusya [100]3 years ago
5 0

Your answer would be D

DaniilM [7]3 years ago
4 0

Answer:

d hope this helps u hhwjs GD jehehj

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How does stem apply to science?<br><br> (i swear if yall just answer for points ima lose it)
vova2212 [387]

STEM is an acronym meaning

Science

Technology

Engineering

Mathematics

One of the main focuses of STEM courses is on science, so you will be learning about various types of science

This is an approach at learning to have students learn all four types of subjects in one class, based on real world applications.

8 0
3 years ago
Where are chemicals found in the home?
vodomira [7]

Answer:

c

Explanation:

chemicals can be found in every part of our lives

6 0
3 years ago
Read 2 more answers
How many moles are in 4561 g of C3H7OH?
d1i1m1o1n [39]

Answer: 76.017 moles

Explanation:

3 0
2 years ago
Metallic copper is formed when aluminum reacts with copper(ii) sulfate. how many grams of metallic copper can be obtained when 5
exis [7]
Answer is: 127 grams <span>rams of metallic copper can be obtained.
</span>Balanced chemical reaction: 2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu.
m(Al) = 54.0 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 54 g ÷ 27 g/mol.
n(Al) = 2 mol.
m(CuSO₄) = 319 g.
n(CuSO₄) = 319 g ÷ 159.6 g/mol.
n(CuSO₄) = 2 mol; limiting reactant.
From chemical reaction: n(CuSO₄) : n(Cu) = 3 : 3 (1 : 1).
n(Cu) = 2 mol.
n(Cu) = 2 mol · 63.55 g/mol.
n(Cu) = 127.1 g.
8 0
3 years ago
The reaction between solid white phosphorous and oxygen produces solid tetraphosphorous decaoxide (P4010).
Alchen [17]

Answer:

oxygen is limiting reactant

Explanation:

Given data:

Mass of phosphorus = 25.0 g

Mass of oxygen = 50.0 g

What is limiting reactant ?

Solution:

Chemical equation:

P₄   +  5O₂       →      P₄O₁₀

Number of moles of P₄:

Number of moles = mass/molar mass

Number of moles = 25.0 g/ 123.89 g/mol

Number of moles = 0.20 mol

Number of moles of  O₂:

Number of moles = mass/molar mass

Number of moles = 50.0 g/ 32 g/mol

Number of moles = 1.56 mol

now we will compare the moles of reactants with product:

        P₄          :            P₄O₁₀

         1           :              1

      0.20       :          0.20

      O₂           :         P₄O₁₀

       5            :         1

     1.56         :        1/5×1.56 = 0.312 mol

Less number of moles of product are formed by the oxygen thus it will act as limiting reactant.

8 0
3 years ago
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