12.5 mols of glucose are in 5 liters of the 2.5 M solution.
Answer: <em>5.47177</em>
<em>For every Mile there is 1.60934 Kilometers</em>
<em>so we take 3.4 and multiply it by 1.60934</em>
<em />
<em>3.4 x 1.60934</em>
<em>= 5.47177 Km</em>
Answer:
Explanation:
Hello.
In this case, when ribose (C₅H₁₀O₅) yields carbon dioxide (CO₂) we write:
Which needs to be balanced by adding water and hydrogen ions:
You can also see that there are 20 transferred electrons, since the carbon atoms in the ribose have 0 as their oxidation state and the carbon atoms in the carbon dioxide have +4 as the oxidation state, thus, each carbon transfers 4 electrons, a five carbon atoms transfer 20 electrons overall.
In such a way, since the carbon is increasing its oxidation state, such half reaction is an oxidation half reaction.
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Answer:
i) The pCa before initiating the titration is 2.6
ii) The pCa is 6.67
Explanation:
please look at the solution in the attached Word file