Lets calculate the initial speed of the block. We know that kinetic energy is given by:
Solving for v₀:
If the speed after it hits a wall is half its original speed then:
v = v₀/2 = 2 m/s / 2 = 1 m/s
Then the kinetic energy at this point is:
The inetic energy of this object at this point is 0.5 J.
Answer:
Cat with 6 kg sitting on a 30 meter hill has greater potential energy.
Explanation:
gravitational potential energy (J) = mass (kg) × gravitational field × height (m)
<h3 /><h3><u>Note</u>:</h3>
gravitational field in Earth is 10 N/kg = <u>fixed unit</u>
<h3 /><h3><u>Given</u>:</h3>
1st Cat: 4 kg
2nd Cat: 6 kg
Both of their height is 30 meters.
<h3><u>Solve for g.p.e</u>:</h3>
1st cat = mgh = 4 × 10 × 30 = 1200 Joules
2nd cat = mgh = 6 × 10 × 30 = 1800 Joules
I’m pretty sure you times them so 1 with A, 2 with e, 3 with C, and 4 with B
Answer:
The two chairs and those sitting on them will move in nearly opposite directions at almost the same speed (assuming that the wheels can only move into two directions - front or back and assuming that the weight of both people are almost the same)
Explanation:
Newton's Third Law states that If an object X exerts a force on object Y, then object Y must exert a force of equal magnitude and opposite direction back on object X.
In other words, when force is applied from source A at B and in direction of B, B also simultaneously returns the force on B and in the direction of B.
This law applies when we jump off the ground when a rocket takes off from the earth into space, etc.
While standing, the body pushes on the earth with a force equal to its own weight. If the ground underneath the body does not meet that force in an equal and opposite direction, both standing on the earth will fall into the earth, with the earth caving underneath it.
You can see why it is important to have a strong foundation for a building and why the depth and strength of the foundation will depend on how much weight is going on it.
Cheers!
Answer:
W = 0.842 J
Explanation:
To solve this exercise we can use the relationship between work and kinetic energy
W = ΔK
In this case the kinetic energy at point A is zero since the system is stopped
W = K_f (1)
now let's use conservation of energy
starting point. Highest point A
Em₀ = U = m g h
Final point. Lowest point B
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
mg h = K
to find the height let's use trigonometry
at point A
cos 35 = x / L
x = L cos 35
so at the height is
h = L - L cos 35
h = L (1-cos 35)
we substitute
K = m g L (1 -cos 35)
we substitute in equation 1
W = m g L (1 -cos 35)
let's calculate
W = 0.500 9.8 0.950 (1 - cos 35)
W = 0.842 J
