Answer:
Explanation:
a). Find the graph attached for the motion.
b). If a shopper walk 5.4 m westwards then 7.8 m eastwards,
Distance traveled by the shopper = Distance traveled in eastwards + Distance traveled westwards
= 5.4 + 7.8
= 13.2 m
c). Displacement of the shopper = Distance walked westwards - Distance traveled eastwards
= 5.4 - 7.8
= -2.4 m
Therefore, magnitude of the displacement of the shopper is = 2.4 m
And the direction of the displacement is eastwards.
The mixing ratio is 6.
To find the answer, we have to know about the mixing ratio.
<h3>
What is mixing ratio?</h3>
- The mixing ratio must be calculated in a complex manner.
- A saturated vapor pressure (es) for values of air temperature and an actual vapor pressure (e) for values of dewpoint temperature must be determined in order to determine the mixing ratio.
- The air temperature and/or dewpoint temperature must first be converted to degrees Celsius (°C) before the vapor pressures can be calculated.
- The equation below can be used to determine the relative humidity (rh), as well as the actual mixing ratio and saturated mixing ratio,
where; w is the mixing ratio and w(s) is the saturation mixing ratio.
- In our question, it is given that,
- Thus, the mixing ratio will be,
Thus, we can conclude that, the mixing ratio is 6.
Learn more about mixing ratio here:
brainly.com/question/8791831
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Answer:
During the segments B - C and D - E, the car stopped since the y axis is the distance and the distance stayed the same in between those segments.
For a simpler answer, the flat horizontal lines on the graph are the times when the car was stopped.
Answer: 7022.2kg/m³, yes, I was cheated
Explanation:
Density of an object is defined as the ratio of the mass of the object to its volume. Mathematically;
Density = Mass/Volume
Note that the unit of both mass and volume must be standard unit.
Given mass = 0.0158kg
Dimension of the metal = 5mm×15mm×30mm
Note that 1mm = 0.001m
The volume of the metal will be
0.005×0.015×0.03
= 0.00000225m³
Density = 0.0158/0.00000225
Average density of the metal = 7022.2kg/m³
Since the standard density of Gold is 19,320kg/m³ and is higher than the density prescribed for me, it shows the I was cheated.
Answer:
16.12
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