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Sergeeva-Olga [200]
3 years ago
15

Please help I literally don’t understand

Physics
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

A= 2

B=3

C=4

D=5

E=7

F=8

H=12

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A parallel-plate vacuum capacitor has 8.60 J of energy stored in it. The separation between the plates is 3.80 mm . If the separ
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Answer:

Part a)

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Part b)

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As we know that the energy of capacitor when it is not connected to potential source is given as

U = \frac{Q^2}{2C}

As we know that initial energy is given as

8.60 = \frac{Q^2}{2C}

now we know that capacitance of parallel plate capacitor is given as

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now the new capacitance when distance is changed from 3.80 mm to 1.45 mm

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C' = \frac{C(3.80)}{1.45}

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Part b)

Now if the voltage difference between the plates of capacitor is given constant

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E = \frac{1}{2}C'V^2

E = \frac{1}{2}(2.62C)V^2

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