So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.
Nancy: 5 Stan: 10
5 is 5 years
younger then Stan
And 5 is twice as
young as 10
Answer: 0.0001
It is unlikely to have a month with no aircraft accidents .
Step-by-step explanation:
Given : Mean number of aircraft accidents = 9 per month
The Poisson distribution formula :-
, where 
is the mean of the distribution.
If X = the number of aircraft accidents per month, then the probability that in a month, there will be no aircraft accidents will be :-
Hence, the probability that in a month, there will be no aircraft accidents = 0.0001
Since this is less than 0.5 , therefor it is unlikely to have a month with no aircraft accidents .
It is hard to comprehend your question. As far as I understand:
f(x,y) = e^(-x)
Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.
That is all I understood. It would be easier to understand with a picture or some kind of visual aid.
Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.
Now evaluate,
which evaluates to, 5/6 if I did the math correct. Correct me if I am wrong.
Now integrate this w.r.t. y:
So,
Answer:
I don’t understand
Step-by-step explanation:
