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3 years ago

If Luis performs resistance training, it is likely that his muscles will _____.

Physics

2 answers:

Nitella [24]3 years ago

5 0

Correct answer: B). Hypertrophy

Muscles hypertrophy is a process, which involves an increase in the size of skeletal muscles. There is two type of hypertrophy, these are sarcoplasmic hypertrophy, which aims to increase muscle glycogen storage and the other one is myofibrillar hypertrophy, which increases myofibril size.

Resistance training is a type of physical training, which aims to increase the muscles strength by making muscles resistance against a force or a work. The different type of resistance training includes free weight, resistance bands and weight machines on which workout is done to build resistance.

Natali [406]3 years ago

4 0

I believe the correct answer from the choices listed above is the second option. If Luis performs resistance training, it is likely that his muscles will go through hypertrophy which means growth and development. Hope this answers the question. Have a nice day.

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Jobisdone [24]

Answer:

a) ll and Ill only

Explanation:

Let the mass of the wrench = m

and the mass of the astronaut = M

Initially, the velocity of the astronaut and wrench are zero.

The astronaut throws the wrench in one direction and subsequently recoils back with a velocity in the opposite direction.

Let v and V be the velocity of the wrench and the velocity of the astronaut respectively.

In space, there is no external force acting, the momentum must be conserved.

So, m(0)+M(0)=m(v)+M(V)

So, 0=mv+MV

$\Rightarrow mv=-MV$ ...(i)

Here, the momentum of the wrench = mv, and the momentum of the astronaut= MV. The negative sign showing that both the momentum are in opposite direction.

Therefore, the momentum of the wrench is equal and opposite to the momentum of the astronaut.

According to Newton's second law, the rate of change of momentum = applied force.

Let it take $\Delta t$ seconds to change the momentum.

So, for the wrench

$m(v-0)/\Delta t= F_w \\\\\Rightarrow m(v-0)=F_w\Delta t \\\\\Rightarrow mv=F_w\Delta t \cdots(ii)$

Here, $F_w\Delta t$ is the impulse applied to the wrench.

Similarly, for the astronaut

$M(-V-0)/\Delta t= F_a$ [negative sign (-V) for opposite direction]

$\Rightarrow M(-V-0)=F_a\Delta t \\\\\Rightarrow -MV=F_a\Delta t$

Here, $F_a\Delta t$ is the impulse applied to the astronaut.

So, the impulse on the astronaut.

By using equations (i) and (ii)

$F_a\Delta t=F_w\Delta t$

Therefore, the impulse applied to the wrench is equal and opposite to the impulse applied to the astronaut.

Hence, option (a) is correct.

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efficiency = heat out / heat in

efficiency = 1030 J / 1540 J

efficiency = 0.669

<span>So the efficiency is 0.669</span>

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