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3 years ago

If Luis performs resistance training, it is likely that his muscles will _____.

Physics

2 answers:

Nitella [24]3 years ago

5 0

Correct answer: B). Hypertrophy

Muscles hypertrophy is a process, which involves an increase in the size of skeletal muscles. There is two type of hypertrophy, these are sarcoplasmic hypertrophy, which aims to increase muscle glycogen storage and the other one is myofibrillar hypertrophy, which increases myofibril size.

Resistance training is a type of physical training, which aims to increase the muscles strength by making muscles resistance against a force or a work. The different type of resistance training includes free weight, resistance bands and weight machines on which workout is done to build resistance.

Natali [406]3 years ago

4 0

I believe the correct answer from the choices listed above is the second option. If Luis performs resistance training, it is likely that his muscles will go through hypertrophy which means growth and development. Hope this answers the question. Have a nice day.

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What are dreams, where do they originate from, why do we have dreams, and are they psychic visions or something? Please explain

Slav-nsk [51]

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3 years ago

A radio signal has a frequency of 1.023 x 108 HZ. If the speed of the signal in air is 2.997 x 108m/s, what is the wavelength of

Sladkaya [172]

Answer:

2.93 m (which agrees with answer "C" on the list)

Explanation:

Recall that the speed of the wave equals the product of the wave's length times its frequency. Therefore, the wavelength is going to be the quotient of the speed of the signal divided its frequency:

Wavelength = 2.997 10^8 / 1.023 10^8 = 2.93 m

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3 years ago

How fast is sound when traveling through water?

IgorLugansk [536]

Sound travels 1,480 meters per second, which is about 4.3 times as fast as air. Sound travels much slowly in air. This has to do with the frequency, intensity and amplitude of waves, which are affected differently in water and air.

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3 years ago

A marathon runner runs at a steady 15 km/hr. When the runner is 7.5 km from the finish, a bird begins flying from the runner to

Whitepunk [10]

Answer:

The value is $D = 15 \ km$

Explanation:

From the question we are told that

The speed of the marathon runner is $v = 15 \ km /hr$

The distance from the distance from the finish is $d = 7.5 \ km$

The speed of the bird is $v_b = 30 \ km / hr$

Generally the time taken for the runner to reach the finish is mathematically represented as

$t = \frac{d}{v}$

$t = \frac{7.5}{15}$

$t = \frac{1}{2}$

So the distance covered by the bird is

$D = v_b * t$

$D = 30 * \frac{1}{2}$

$D = 15 \ km$

6 0

3 years ago

16. A 95kg fullback, running at 8.2m/s, collided in midair with a 128 kg defensive tackle moving in the opposite direction. Both

Daniel [21]

a) 779 kg m/s

The momentum of an object is given by:

p = mv

where

m is the mass of the object

v is its velocity

For the fullback before the collision,

m = 95 kg

v = 8.2 m/s

Therefore, his momentum was:

$p=mv=(95)(8.2)=779 kg m/s$

b) -779 kg m/s

After the collision, both the fullback and the tackle come to a stop: this means that their momentum after the collision is zero,

p' = 0

The initial momentum of the fullback was

p = 779 kg m/s

Therefore, his change in momentum is

$\Delta p = p' -p =0-779 = -779 kg m/s$

where the negative sign indicates that the direction is opposite to the initial direction of motion.

c) -779 kg m/s

Here we can apply the law of conservation of momentum. In fact, the total momentum before and after the collision must be conserved. So we can write:

$p_f + p_t = p'$

where

$p_f$ is the initial momentum of the fullback

$p_t$ is the initial momentum of the tackle

p' is the final combined momentum after the collision

We already know that

$p_f = 779 kg m/s\\p' = 0$

Therefore, we can find the tackle's original momentum:

$p_t = p'-p_f = 0-(779) = -779 kg m/s$

where the negative sign indicates that the direction is opposite to the initial direction of motion of the fullback.

e) -6.1 m/s

To find the velocity of the tackle, we can use again the equation of the momentum:

p = mv

where here we have

$p=-779 kg m/s$ is the original momentum of the tackle

m = 128 kg is his mass

Solving the equation for v, we find the tackle's original velocity:

$v=\frac{p}{m}=\frac{-779}{128}=-6.1 m/s$

So, he was moving at 6.1 m/s in the direction opposite to the fullback.

4 0

3 years ago