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Ulleksa [173]
3 years ago
6

Complete the complex dimensional analysis problem to determine the price of one atom of aluminum. A 20cm x 20cm square of alumin

um had a mass of 1.50g. A box of aluminum cost $1.29 and the area of foil in the box is 2.33 m^2. What is the cost of one atom of aluminum?
Chemistry
1 answer:
mixer [17]3 years ago
7 0

$8.09

Because you multiply and subtract to get the answer

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Advocard [28]

Answer:

D.

Explanation:

Decompostion of stone due to acid rain

8 0
3 years ago
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Select the compounds that cannot undergo friedel crafts alkylation. check all that apply. check all that apply. aniline phenol k
mr Goodwill [35]

Freidal craft reaction is the attack of a carbon or carbon chain on aromatic ring with the help of anhydrous AlCl3 to produce alkylated benzene ring.

Only ketone not be able to undergo friedal craft reaction as, it is not aromatic compound whereas all the given reactants are aromatic and gives friedal craft reaction.

5 0
3 years ago
Determine the molarity of 56.00 grams of aluminum nitrate in 450 milliliters of solution?
SVETLANKA909090 [29]

Answer:

4.62 M

Explanation:

Molarity = moles/volumes (L), so you need to find the moles and the volumes in liters.

Finding the volume is easy because you just have to convert mL to L, so the volume is 0.45 L

Next, find the moles. You can do this by using the molar mass of aluminum to convert the grams to moles. The molar mass of aluminum is 26.98 g/mol.

56 g * (1 mol/26.98 g) = 2.08 mol

Now, divide the moles (2.08) by the volume (.45 L)

Molarity = 4.62 M

3 0
3 years ago
A 8L sample of gas at 250 K is cooled to 75 K. What is the volume of the gas after it is cooled?
Stells [14]

by \: Charles'\: law: \:  \\  \frac{v_{1}}{t_{1}}  =  \frac{v_{2}}{t_{2}}  \\

Where v is the volume(in L) and t is the temperature(in °K)

\frac{8}{250}  =  \frac{v_{2}}{75} \\\\4/5 =v_2/3 \\\\\boxed{v_{2} = \frac{12}{5}}\\\\\\\huge{=2.5 l}

7 0
2 years ago
Electron configurations are a shorthand form of an orbital diagram, describing which orbitals are occupied for a given element.
kipiarov [429]

Answer:

[Ar] 3d10 4s2 4p3 is shorthand, 1s22s22p63s23p63d104s24p3 long hang

Explanation:

The shorthand is made using the lowest & closest noble gas, and picking up where it leaves off as follows, and longhand is made from a followed pattern you can easily find

3 0
3 years ago
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