Answer:
A.) 0.34 atm
Explanation:
Change the Celsius to Kelvin:
50.0 C = (273 + 50) = 323 K
22.0 C = ( 273 + 22) = 295 K
Gay-Lussac's Law: (P1/T1) = (P2/T2)
Rearranging that to solve for P2 gives
P2= (P1 x (T2/T1))
=0.370 atm x (295 K / 323 K)
= 0.338 atm
Answer A
Answer:
There isn't anything below, but i can help if you edit the question and put it there
Explanation:
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Answer:
-2.79 × 10³ cal
Explanation:
Step 1: Given data
- Mass of water (m): 35.0 g
- Latent heat of fusion of water (L): -79.7 cal/g
Step 2: Calculate the heat required to freeze 35.0 g of water
We have 35.0 g of liquid water and we want to freeze it, that is, to convert it in 35.0 g of ice (solid water), at 0 °C (melting point). We can calculate the heat (Q) that must be released using the following expression.
Q = L × m
Q = -79.7 cal/g × 35.0 g
Q = -2.79 × 10³ cal
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