If you’ve been vaping for a while now, you may be craving some new vape juice flavors to try with your favorite RDA, RTA, or Box Mod.
You might find that ordering large batches of your all day vape juice flavors can prove a bit on the expensive side, particularly if your tastes run toward the premium e juice priced at over $20 per bottle.
Surely there must be a better way than taking out payday loans to get your hands on that Peanut Butter Crunch-flavored creation you just have to have in your sub-ohm tank?
Fortunately, when you know how to make homemade vape juice it can be a fun and fascinating hobby that has the delightful side effect of saving you loads of cash using cheap vape juice.
Many people hear “diy vape juice” and get visions of a mad scientist in a dank lab constantly flirting with explosion by mixing volatile chemicals while laughing insanely.
The reality is that it’s relatively easy to learn how to make your own vape juice at home, and we’re going to attempt to cover all the facets involved.
Are you interested in making your own e juice?
Answer:
it is because solid is.in a fixed shape so it is easier to separate a solid from another solid compared to a liquid from another liquid
First; use the relationship of molarity and moles/liter to find the moles of the solution.
so 0.600M ×0.030L = 0.018 moles
Then use the mole to mole ratio of lithium to lithium carbonate
0.18 × (2 Li ÷1 Li2CO3) = 0.036
and then multiply by Avogadro's number to find the ions of lithium
0.036 moles × (6.022×10^{23} ) = 2.167 ×10∧22 ions Li
Answer:
C.) The less dense the object, the faster the heat will transfer.
Answer: 234.4K
Explanation:
Given that,
Original volume of gas (V1) = 5.00 L
Original temperature of gas (T1) = 20.0°C
[Convert 20.0°C to Kelvin by adding 273
20.0°C + 273 = 293K]
New volume of gas (V2) = 4.0L
New temperature of gas (T2) = ?
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
5.00L/293K = 4.0L/T2
To get the value of T2, cross multiply
5.00L x T2 = 293K x 4.0L
5.00L•T2 = 1172L•K
Divide both sides by 5.00L
5.00L•T2/5.00L = 1172L•K/5.00L
T2 = 234.4K
Thus, the new temperature of the gas is 234.4 Kelvin
