Solution :
In the process to isolate gold that has a 80 percent yield, a 3.00 g of Au is being isolated.
That is, the actual yield of Au is 3. 00 g
Therefore, we need to find the theoretical yield.
As we know,
As actual yield = 3.00 g
percent yield = 80 %
So, theoretical yield = 
= 3.75 g
Thus he should be able to get 3.75 g which is the theoretical yield of Au.
Given:
K = 0.71 = Kp
The reaction of sulphur with oxygen is
S(s) + O2(g) ---> SO2(g)
initial Pressure 6.90 0
Change -x +x
Equilibrium 6.90-x x
Kp = pSO2 / pO2 = 0.71 = x / (6.90-x)
4.899 - 0.71x = x
4.899 = 1.71x
x = 2.86 atm = pressure of SO2 formed
temperature = 950 C = 950 + 273.15 K = 1223.15 K
Volume = 50 L
Let us calculate moles of SO2 formed using ideal gas equation as
PV = nRT
R = gas constant = 0.0821 L atm / mol K
putting other values
n = PV / RT = 2.86 X 50 / 1223.15 X 0.0821 = 1.42 moles
Moles of Sulphur required = 1.42 moles
Mass of sulphur required or consumed = moles X atomic mass of sulphur
mass of S = 1.42 X 32 = 45.57 grams or 0.04557 Kg of sulphur
Answer:
Robert Hooke
Explanation:
He saw a series of walled boxes that reminded him of the tiny rooms, or cellula, occupied by monks.
We are given with a hydrate with a mass of 6 grams and after heating the mass and cooling afterward, the mass went down to 3.27 grams. The amount of water in the hydrate thus is 6-3.27 g or 2.73 grams.That is equivalent to 45.5 percent by mass water.
The correct answer is (4) A large amount of energy is produced in a nuclear fission reaction.
Choice (1) is false, the products are radioactive, and often have to be buried underground for long periods of time. Choice (2) is false, because the reactants are often unstable to allow them to decay and release energy. Choice (3) is false, because the radioactive substances can affect living organisms.
