What is physical weathering?: Physical weathering is a term used in science that refers to the geological process of rocks breaking apart without changing their chemical composition. Over time, movements of the Earth and environment can break apart rock formations, causing physical weathering.
How do trees break down solid rock?: When the water freezes it expands and the cracks are opened a little wider. Over time pieces of rock can split off a rock face and big boulders are broken into smaller rocks and gravel. This process can also break up bricks on buildings. Chemical weathering decomposes or decays rocks and minerals.
What causes the most common type of physical weathering?: Physical Weathering. Physical weathering is caused by the effects of changing temperature on rocks, causing the rock to break apart. ... There are two main types of physical weathering: Freeze-thaw occurs when water continually seeps into cracks, freezes and expands, eventually breaking the rock apart.
what percent does water expand?: 9%
How does water break down apart a rock?: Flowing water can move rocks, causing them to rub together and wear down into rounded shapes. When plants grow in cracks in a rock, their roots can widen the cracks and force the rock apart. Rainwater fills small cracks in a rock. As the water freezes, it expands, widening the cracks and splitting apart the rock.
P.s. You could've just googled these.
Answer:
THE PRESSURE OF THE TIRE ON THE TRIP HOME AT THE ROAD SURFACE TEMPERATURE OF 32°C IS 160 kPa.
Explanation:
Initial Pressure = 75 kPa
Initial temperature = 15 °C
Final temperature = 32 °C
Final pressure = unknown
Using the combined equation of gases;
P1V1/T1 = P2V2/ T2
Since the tire will have the same volume of air in it showing that volume of constant both at the repair shop and on the road surface.
The relationship between pressure and temperature is used with constant volume.
P1/T1 = P2/ T2
75 kPa / 15 °C = P2 / 32 °C
P2 = 75 kPa * 32 °C / 15 °C
P2 = 2400 kPa °C / 15 °C
P2 = 160 kPa.
So therefore, the pressure of the tire on the trip home when the temperature of the road surface is 32°C is 160 kPa.
Answer:
P₂ = 1.0 atm
Explanation:
Boyles Law problem => P ∝ 1/V at constant temperature (T).
Empirical equation
P ∝ 1/V => P = k(1/V) => k = P·V => for comparing two different case conditions, k₁ = k₂ => P₁V₁ = P₂V₂
Given
P₁ = 1.6 atm
V₁ = 312 ml
P₂ = ?
V₂ = 500 ml
P₁V₁ = P₂V₂ => P₂ = P₁V₁/V₂ =1.6 atm x 312 ml / 500ml = 1.0 atm
