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Ad libitum [116K]
3 years ago
15

chemistry student needs of thiophene for an experiment. She has available of a w/w solution of thiophene in carbon tetrachloride

. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Chemistry
1 answer:
kumpel [21]3 years ago
4 0

The question is incomplete, here is the complete question:

A chemistry student needs 75 g of thiophene foran experiment. He has available 0.50 kg of a 29.3% w/w solution of thiophene in carbon tetrachloride.

Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.

<u>Answer:</u> The mass of solution the student should use is 255.97 grams

<u>Explanation:</u>

We are given:

Mass of thiophene needed = 75 gram

29.3 % w/w thiophene solution

This means that 29.3 grams of thiophene is present in 100 grams of solution

Applying unitary method:

If 29.3 grams of thiophene is present in 100 grams of solution

So, 75 grams of thiophene will be present in = \frac{100}{29.3}\times 75=255.97g

Given amount of solution = 0.50 kg = 500 grams   (Conversion factor:  1 kg = 1000 g)

Hence, the mass of solution the student should use is 255.97 grams

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The planet Mercury takes 176 days to do one spin around its pole. Compared to the Earth,
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Answer:

The sun would appear to move more slowly across Mercury's sky.

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Since the angular speed ω = 2π/T where T = period

So on  Mercury, T' = 176days = 176 days × 24 hr/day × 60 min/hr × 60 s/min = ‭15,206,400‬ s

So, ω' = 2π/T'

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3 years ago
How many moles are in 7.2 x 10^23 carbon molecules?
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Explanation:

It is known that in 1 mole there are 6.023 \times 10^{23} atoms or molecules.

It is given that there are 7.2 \times 10^{23} carbon molecules. Therefore, calculate the moles as follows.

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Thus, we can conclude that there are 1.196 mol in 7.2 \times 10^{23} carbon molecules.

7 0
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