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iVinArrow [24]
3 years ago
14

Please help me I will give a brainleist to anyone who answers​

Chemistry
1 answer:
tekilochka [14]3 years ago
4 0

Answer:

4

Explanation:

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Montano1993 [528]
 I think this is what you're after:

 Cs(g) → Cs^+ + e⁻ ΔHIP = 375.7 kJ mol^-1 [1] 


Convert to J and divide by the Avogadro Const to give E in J per photon 


E = 375700/6.022×10^23 = 6.239×10^-19 J 


Plank relationship E = h×ν E in J ν = frequency (Hz s-1) 


Planck constant h = 6.626×10^-34 J s 


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Problem PageQuestion Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume
IgorC [24]

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 3.16 L of chlorine were consumed at STP.

Be sure your answer has the correct number of significant digits.

Answer: Thus volume of carbon tetrachloride that would be produced is 0.788 L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm  (at STP)

V = Volume of gas = 3.16 L

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K=

n=\frac{PV}{RT}

n=\frac{1atm\times 3.16L}{0.0820 L atm/K mol\times 273K}=0.141moles

CH_4+4Cl_2\rightarrow 4HCl+CCl_4

According to stoichiometry:

4 moles of chlorine produces = 1 mole of carbon tetrachloride

Thus 0.141 moles of methane produces = \frac{1}{4}\times 0.141=0.0352 moles of carbon tetrachloride

volume of carbon tetrachloride =moles\times {\text {Molar volume}}=0.0352mol\times 22.4L/mol=0.788L

Thus volume of carbon tetrachloride that would be produced is 0.788 L

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