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Advocard [28]
3 years ago
12

Which action changes the identity of the substance referenced?

Chemistry
1 answer:
DerKrebs [107]3 years ago
5 0
Corroding iron.  The reason why iron corrodes is that it reacts with the oxygen in the air to create iron oxide which is what we call rust.  when iron turns to rust, the chemical identity of the iron changes.  
when you break ice, the ice is still ice.  that water did not change into something else.  when you run a current through copper, the electrons in the copper move due to the voltage but the copper is not changing.  After the circuit stops, the copper wires are still made out of copper (the copper did not undergo a chemical change).  When you melt gold, the gold is only going from solid form to liquid form.  The gold has not changed chemically, it just underwent a phase change.
I hope this helps.  Let me know if anything is unclear.
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Make a checklist of eight good characteristics of a experiment.
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6 0
4 years ago
A 216-L cylinder holds propane gas at 184.8 kPa of pressure and 127°C. How many moles of propane are in the cylinder?
lbvjy [14]

Answer:

12 moles of propane.

Explanation:

From the question given above, the following data were obtained:

Volume (V) = 216 L

Pressure (P) = 184.8 KPa

Temperature (T) = 127 °C

Number of mole (n) =?

Next, we shall convert 127 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 127 °C

T(K) = 127 + 273

T(K) = 400 K

Finally, we shall determine the number of mole of propane gas in the container. This can be obtained as follow:

Volume (V) = 216 L

Pressure (P) = 184.8 KPa

Temperature (T) = 400 K

Gas constant (R) = 8.314 L.KPa/Kmol

Number of mole (n) =?

PV = nRT

184.8 × 216 = n × 8.314 × 400

39916.8 = n × 3325.6

Divide both side by 3325.6

n = 39916.8 / 3325.6

n = 12 moles

Thus, 12 moles of propane is present in the cylinder

8 0
3 years ago
Consider the Van der Vaals equation of state: (????+????????????)(????−????)=???????????? where p is pressure, V is volume, n is
yanalaym [24]

Answer:

Units of a = \frac{atm\ L^2}{mol^2}

Units of b = \frac{L}{mol}

Explanation:

The Van der Waal's equation  is:-

\left(P+\frac{an^2}{V^2}\right)\left(V-nb\right)=nRT

Where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value

a and b are van der Waal's constant

If pressure is taken in atm and volume in L. So,

P+\frac{an^2}{V^2} represents the pressure correction term. Then,

Units of a = \frac{atm\ L^2}{mol^2}

V-nb represents the volume correction term. Then,

Units of b = \frac{L}{mol}

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3 years ago
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