Answer:
This is about 176 times the weight of the froghopper.
Explanation:
the grasshopper converts kinetic energy into earth gravitational potential energy
u=mgh
u=12*10^-3*9.8*0.7
=8.23*10^-2
using the Work energy principle
equating the kinetic energy to the potential energy
k +U+w=K2+u2
K+0+0=0+U2
k=8.23*10^-2
force exerted by the grasshopper on the round will be given by tis equation
(F-mg)Ycos
=k
(F-12*10^-3*9.8)*0.004cos 0=8.23*10^-2
F=20.7N
from newtons third law of motion, action and reaction are equal and opposite
F=-20.7N
comparing the forces by the two bodies
F:mg
-20.7:-12*10^-3*9.8
the magnitude of the force applied by the grasshopper is found to be 176 times the gravitational force
1- Kinetic , Mass , Speed
2- Speed
3- Speed, Mass
4- Mass, More
5- Transferred, collide
6- Kinetic, electricity
7- Transferred, Destroyed
:)
Answer:
3.69 m/s
Explanation:
Forces :
mgsin Θ - mumgcosΘ = ma
g x sinΘ - mu x g x cosΘ = a
9.8 x sin 21 - 0.53 x 9.8 x cos 21 = a
a = -1.337 m/s²
so you have final velocity = 0 m/s
initial velocity = ? m/s
Given d = 5.1 m
By kinematics
vf² = vo² + 2ad
0 = vo² + 2 x -1.337*5.1
vo = 3.69 m/s