Answer:
The answer is C 1.8V and 0.38A
Answer:
5.71×10¹⁴ Hz
Explanation:
Applying,
v = λf................. Equation 1
Where v = speed of the electromagnetic radiation, λ = wavelength of the electromagnetic radiation, f = frequency
make f the subject of the equation
f = v/λ............. Equation 2
From the question,
Given: λ = 525 nm = 5.25×10⁻⁷ m,
Constant: Speed of electromagnetic wave (v) = 3.0×10⁸ m/s
Substitute these values into equation 2
f = (3.0×10⁸)/(5.25×10⁻⁷)
f = 5.71×10¹⁴ Hz
Hence the frequency of light is 5.71×10¹⁴ Hz
Answer:
1.05m or 105cm
Explanation:
Using the hooke's law equation as follows;
F = –k.x
Where;
F = force (N)
x = extension length (m)
k = constant of proportionality (N/m)
According to the information given in this question;
Displacement (x) = 85cm = 85/100 = 0.85m
Force = 12500N
Using F = kx, we find the proportionality constant
k = F/x
K = 12500/0.85
K = 14705.8N/m.
Also, since K = 14705.8N/m, the displacement (x), when the force increases to 15500N is;
F = kx
x = F/k
x = 15500/14705.8
x = 1.05m or 105cm
Answer:
Approximately 18 volts when the magnetic field strength increases from 
to 
at a constant rate.
Explanation:
By the Faraday's Law of Induction, the EMF 
that a changing magnetic flux induces in a coil is:
,
where
is the number of turns in the coil, and
is the rate of change in magnetic flux through this coil.
However, for a coil the magnetic flux 
is equal to
,
where
is the magnetic field strength at the coil, and
is the area of the coil perpendicular to the magnetic field.
For this coil, the magnetic field is perpendicular to coil, so 
and 
. The area of this circular coil is equal to 
.
doesn't change, so the rate of change in the magnetic flux through the coil depends only on the rate of change in the magnetic field strength . The size of the magnetic field at the instant that 
will not matter as long as the rate of change in is constant.
.
As a result,
.
