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arsen [322]
3 years ago
9

Debby and Ben took different routes to travel from Point A to Point E. Debby took the route along A, B, C, D, and E. Ben took th

e route along A, G, F, and E. Debby and Ben both took 4 hours to complete their walk. Their routes are shown. (3 points)
Which statement is true about Debby and Ben's average speed?
Ben and Debby's average speed was the same.
Debby's average speed was twice Ben's average speed.
Ben's average speed was twice Debby's average speed.
Debby's average speed was three times Ben's average speed.

Physics
2 answers:
Nata [24]3 years ago
8 0
Bens was twice debbys speed.
svetlana [45]3 years ago
4 0

Answer:

Ben's average speed was twice Debby's average speed.

Explanation:

Ben covered a total distance of 16 miles (10+4+2) and Debby covered 8 miles (3+2+2+1) which is half of what Ben covered. As they both reached the place in the same amount of time it tells us Ben was faster.

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An ideal parallel-plate capacitor consists of a set of two parallel plates of area A separated by a very small distance d. When
sleet_krkn [62]

Answer:

2dQ²/2εA = 2U₀

Explanation:

The energy stored in the ideal parallel plate capacitor U = Q²/2C. For a parallel plate capacitor, C = εA/d where A is the area between the plates and D is the distance between them. So

U = Q²/2C = Q²/2εA/d = dQ²/2εA. At distance d₁ = d, U = U₀,

U₀ = dQ²/2εA,

When d₂ = 2d, U₁ = d₂Q²/2εA = 2dQ²/2εA = 2U₀

3 0
3 years ago
A mailman performed 296 J of work lifting a box of 1.6 m. How much force did the mailman use?
Rus_ich [418]
185 newtons because (W=Fd so W/d=F)296/1.6=185
7 0
3 years ago
What type of line connects the north and South Pole?
Aloiza [94]

Answer:

lines of longitude

Explanation:

8 0
3 years ago
You have gas in a container with a movable piston. The walls of the container are thin enough so that its temperature stays the
bearhunter [10]

Answer:

New pressure of the gas increases by 26.5% with respect to initial pressure, new volume decreases 27% with respect to initial volume and new temperature decreases 8% with respect to initial volume.

Explanation:

If we assume the gas is a perfect gas we can use the perfect gas equation:

PV=nRT

  • For Isothermal process:

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}(1)

Where subscripts 1 shows before the isothermal process and 2 after it, because isothermal means constant temperature T1=T2, and pressure increases by 10% means P2=1,1*P1, using these facts on (1) we have:

V_{2}=\frac{V_{1}}{1.1} (2)

  • For Isobaric process:

\frac{P_{2}V_{2}}{T_{2}}=\frac{P_{3}V_{3}}{T_{3}} (3)

Where subscripts 2 shows before the isobaric process and 3 after it, because isobaric means constant pressure P2=P3, and volume decreases by 20% means V3=0.8*V2, using these facts on (3) we have:

T_{3}=0.8T_{2} (4)

  • For Isochoric process:

\frac{P_{3}V_{3}}{T_{3}}=\frac{P_{4}V_{4}}{T_{4}} (5)

Where subscripts 3 shows before the isochoric process and 4 after it, because isochoric means constant volume V3=V4, and temperature increases by 15% means T4=1.15*T3, using these facts on (5) we have:

P_{4}=1.15P_{3} (6)

So now because P4=1.15*P3, P2=P3 and P2=1.1*P1:

P_{4}=1.15*1.1P_{1}=1.265P1

This is, the new pressure of the gas increases by 26.5%  with respect to initial pressure.

Similarly, we have V3=V4, V3=0.8*V2 and V1=1,1*V2:

V_{4}=\frac{0.8}{1.1}V_{1}=0.72V1

so the final volume decreases 27% with respect to initial volume.

T4=1,15*T3, T3=0.8*T2 and T1=T2:

T_{4}=1.15*0.8T_{1}=0.92T1

The new temperature decreases 8% with respect to initial volume.

3 0
3 years ago
Glass is transparent to visibile light under normal conditions; however, at extremely high intensities, glass will absorb most o
8_murik_8 [283]

Answer:

3 photons

Explanation:

The energy of a photon E can be calculated using this formula:

E=\frac{hc}{\lambda}

Where h corresponds to Plank constant (6.626070x10^-34Js), c is the speed of light in the vacuum (299792458m/s) and \lambda is the wavelength of the photon(in this case 800nm).

E=\frac{hc}{\lambda}=\frac{(6.626070\times10^{-34})(299792458)}{800\times10^{-9}}=\frac{1.986445812\times10^-25}{800}=2.483057265\times10^{-19}J

Tranform the units

1eV=1.602176634\times10^{-19}J\\2.483057265\times10^{-19}J(\frac{1eV}{1.602176634\times10^{-19}J})=1.549802445eV

The band Gap is 4eV, divide the band gap between the energy of the photon:

\frac{4ev}{1.549802445eV}=2.508974118

Rounding to the next integrer: 3.

Three photons are the minimum to equal or exceed the band gap.

4 0
3 years ago
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