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nirvana33 [79]
4 years ago
13

An automobile company displays a die-cast model of its first car, made from 8.70 kg of iron. To celebrate its hundredth year in

business, a worker will recast the model in solid gold from the original dies. What mass of gold is needed to make the new model?
Physics
1 answer:
lakkis [162]4 years ago
7 0

Answer:

21.28 kg

Explanation:

Density of iron = 7890 kg/m³ =\rho_i

Mass of iron = 8.7 kg=m_i

Volume of gold = Volume of iron = v

Density = Mass / Volume

\rho_i=\frac{m_i}{v}\\\Rightarrow v=\frac{m}{\rho}\\\Rightarrow v=\frac{8.7}{7890}

Density of gold = 19300 kg/m³=\rho_g

Mass of iron =m_i

\rho_g=\frac{m_g}{v}\\\Rightarrow m=\rho_g v\\\Rightarrow m_g=19300\times \frac{8.7}{7890}\\\Rightarrow m_g=21.28\ kg

Mass of gold needed to make the new model is 21.28 kg

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Answer:

If you use the same force to push a truck and a car, the car will have more acceleration than the truck because the car has less mass.

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Suppose two people are walking and among the two people, if one is heavier than the other, then the one weighing heavier will walk slower because the acceleration of the person weighing lighter is greater.

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Explanation:

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3 years ago
The seatbelt across your chest should have about ______ fist width of slack
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The correct answer is option (c) i.e. one

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3 years ago
A diverging lens with a focal length of 14 cm is placed 12 cm to the right of a converging lens with a focal length of 21 cm. An
IRINA_888 [86]

Answer:

-0.233 m left of diverging lens and ( 0.12 - 0.233 ) = -113 m left of conversing

and

0.023 m  right of diverging lens

Explanation:

given data

focal length f2 = 14 cm = -0.14 m

Separation s = 12 cm = 0.12 m

focal length f1 = 21 cm = 0.21 m

distance u1 = 38 cm

to find out

final image be located and Where will the image

solution

we find find  image location i.e v2

so by lens formula v1 is

1/f = 1/u + 1/v     ...............1

v1 = 1/(1/f1 - 1/u1)

v1 = 1/( 1/0.21 - 1/0.38)

v1 = 0.47 m

and

u2 = s - v1

u2 = 0.12 - 0.47

u2 = -0.35

so from equation 1

v2 = 1/(1/f2 - 1/u2)

v2 = 1/(-1/0.14 + 1/0.35)

v2 = -0.233 m

so -0.233 m left of diverging lens and ( 0.12 - 0.233 ) = -113 m left of conversing

and

for Separation s = 45 cm = 0.45 m

v1 = 1/(1/f1 - 1/u1)

v1 =0.47 m

and

u2 = s - v1

u2 = 0.45 - 0.47 =- 0.02 m

so

v2 = 1/(1/f2 - 1/u2)

v2 = 1/(-1/0.14 + 1/0.02)

v2 = 0.023

so here 0.023 m  right of diverging lens

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Answer:

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