Answer:
1. 24375 N/C
2. 2925 V
Explanation:
d = 12 cm = 0.12 m
F = 3.9 x 10^-15 N
q = 1.6 x 10^-19 C
1. The relation between the electric field and the charge is given by
F = q E
So, ![E=\frac{F}{q}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BF%7D%7Bq%7D)
![E=\frac{3.9 \times 10^{-15}}{1.6 \times 10^{-19}}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B3.9%20%5Ctimes%2010%5E%7B-15%7D%7D%7B1.6%20%5Ctimes%2010%5E%7B-19%7D%7D)
E = 24375 N/C
2. The potential difference and the electric field is related by the given relation.
V = E x d
where, V be the potential difference, E be the electric field strength and d be the distance between the electrodes.
By substituting the values, we get
V = 24375 x 0.12 = 2925 Volt
Answer:
9.3 g/cm³
Explanation:
First, convert kg to g:
0.485 kg × (1000 g / kg) = 485 g
Density is mass divided by volume:
D = (485 g) / (52 cm³)
D = 9.33 g/cm³
Rounding to two significant figures, the density is 9.3 g/cm³.
Answer:
They sh0uld g0 t0 the reactor and then, see what the issue is...
Explanation:
then, see if they can fix the problem, im sorry if its wr0ng.
Answer:
Venus and Earth
Explanation:
The force of gravity depends on your mass AND the mass of the planet you stand on. Earth and Venus are about the same size, so they have about the same mass. If you go to Venus, your mass hasn't changed, and the planet mass is almost the same as earth- so the force of gravity on you (AKA your weight) will be the same.
Answer:
a
The direction of the wave propagation is the negative z -axis
b
The amplitude of electric and magnetic field are
,
respectively
Explanation:
According to right hand rule, your finger (direction of electric field) would be pointing in the positive x-axis i.e towards your right let your palms be face toward the direction of the magnetic field i.e negative y-axis (toward the ground ) Then anywhere your thumb stretched out is facing is the direction of propagation of the wave here in this case is the negative z -axis
The Intensity of the wave is mathematically represented as
![I = \frac{1}{2} c \epsilon _O E_{rms}^2](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20c%20%5Cepsilon%20_O%20E_%7Brms%7D%5E2)
Given that ![I = 7.43 \frac{kW}{cm^2} = 7.43 \frac{*10^3}{*10^-{4} }= 7.43*10^7 \frac{W}{m^2}](https://tex.z-dn.net/?f=I%20%3D%207.43%20%5Cfrac%7BkW%7D%7Bcm%5E2%7D%20%3D%20%207.43%20%5Cfrac%7B%2A10%5E3%7D%7B%2A10%5E-%7B4%7D%20%7D%3D%207.43%2A10%5E7%20%5Cfrac%7BW%7D%7Bm%5E2%7D)
Making
the subject we have
![E_{rms} = \sqrt{\frac{I}{0.5*c*\epsilon_o} }](https://tex.z-dn.net/?f=E_%7Brms%7D%20%3D%20%5Csqrt%7B%5Cfrac%7BI%7D%7B0.5%2Ac%2A%5Cepsilon_o%7D%20%7D)
Substituting values as given on the question
![E_{rms} = \sqrt{\frac{7.43 *10^7[\frac{W}{m^2} ]}{0.5 * 3.08*10^8 *8.85*10^{-12}} }](https://tex.z-dn.net/?f=E_%7Brms%7D%20%3D%20%5Csqrt%7B%5Cfrac%7B7.43%20%2A10%5E7%5B%5Cfrac%7BW%7D%7Bm%5E2%7D%20%5D%7D%7B0.5%20%2A%203.08%2A10%5E8%20%2A8.85%2A10%5E%7B-12%7D%7D%20%7D)
![= 2.37*10^5 \ V/m](https://tex.z-dn.net/?f=%3D%202.37%2A10%5E5%20%5C%20V%2Fm)
The amplitude of the electric field is mathematically represented as
![A_E = \sqrt{2} * E_{rms}](https://tex.z-dn.net/?f=A_E%20%3D%20%5Csqrt%7B2%7D%20%2A%20E_%7Brms%7D)
![= \sqrt{2} * 2.37*10^5](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B2%7D%20%2A%202.37%2A10%5E5)
![A_E= 3.35*10^5 V/m](https://tex.z-dn.net/?f=A_E%3D%203.35%2A10%5E5%20V%2Fm)
The amplitude of the magnetic field is mathematically represented as
![A_M = \frac{A_E}{c}](https://tex.z-dn.net/?f=A_M%20%3D%20%5Cfrac%7BA_E%7D%7Bc%7D)
Substituting value
![A_M = \frac{3.35 *10^5}{3.0*10^8}](https://tex.z-dn.net/?f=A_M%20%3D%20%5Cfrac%7B3.35%20%2A10%5E5%7D%7B3.0%2A10%5E8%7D)
![A_M= 1.12 *10^{-3} T](https://tex.z-dn.net/?f=A_M%3D%201.12%20%2A10%5E%7B-3%7D%20T)