Answer:
.079 moles of Nirogen gas (N2)
Explanation:
You can see from the equaton that each ONE mole of N2 produces TWO moles of NH3.
Find the number of moles of NH3 produced.
Using Periodic Table : Mole wt of NH3 = 17 gm/mole
2.7 gm / 17 gm/mole = .1588 moles
One half as many moles of N2 are needed = .079 moles
THE CORRDCT ANSWER IS TRUE
Answer:
Empirical formula of C4H8O2, is the answer
Explanation:
Ok percent error is abs(calculated-actual)/actual(100%)
So 1.5/96 *100%
