rerouting a river the the correct option
The reaction is
Zn(s) + 2MnO₂(s) + H₂O(l) ⟶ Zn(OH)₂(s) + Mn₂O₃(s)
The reactants are Zn(s) and MnO₂(s) while Zn(OH)₂(s) and Mn₂O₃(s) products.
Let's see the oxidation state of each compound.
sum of the o.s. of the each element of compound = charge of the compound
O.s of O = -2
O.s of OH⁻ = -1
O.s of Zn(s) = 0
O.s of Mn in MnO₂(s) = x
x + (-2) * 2 = 0
x = +4
O.s of Zn in Zn(OH)₂(s) = a
a + (-1) * 2 = 0
a = +2
O.s of Mn in Mn₂O₃(s) = b
2*b + (-2) * 3 = b
2b = 6
b = +3
Since the O.s is reduced in Mn from +4 to +3, the reduced species is Mn₂O₃(s).
<span>The notion of hybrid orbitals was "invented" by Linus Pauling in 1931 to explain the observed geometry of mostly organic molecules. Today, we find that hybrid orbitals are pretty much confined to the central atoms found in the second period of the periodic table. Periods 3 and up .... not so much.
(a) H2O ..... O is the central atom, tetrahedral, sp3 hybridization
(b) PBr5 .... P is the central atom, maybe sp2 for the three equatorial bonds *
(c) COCl2.. C is the central atom, trigonal planar, sp2 hybridization </span>
