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d1i1m1o1n [39]
3 years ago
6

Assume the impedance of a circuit element is Z = (3 + j4) Ω. Determine the circuit element’s conductance and susceptance.

Engineering
1 answer:
djyliett [7]3 years ago
8 0

Answer:

B. G = 333 mS, B = j250 mS

Explanation:

impedance of a circuit element is Z = (3 + j4) Ω

The general equation for impedance

Z = (R + jX) Ω

where

R = resistance in ohm

X = reactance

R = 3Ω  X = 4Ω

Conductance = 1/R while Susceptance = 1/X

Conductance = 1/3 = 0.333S

= 333 mS

Susceptance = 1/4 = 0.25S

= 250mS

The right option is B. G = 333 mS, B = j250 mS

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Answer:

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import java.util.Scanner; // to get input from user

public class DrawHalfArrow{ // start of the class half arrow

public static void main(String[] args) { // starts of main() function body

    Scanner scnr = new Scanner(System.in); //reads input

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arrowBaseWidth = scnr.nextInt();

/* while loop to continue asking user for an arrow head width until the value entered is greater than the value of arrow base width */

while (arrowHeadWidth <= arrowBaseWidth) {

    System.out.println("Enter arrow head width: ");

    arrowHeadWidth = scnr.nextInt(); }

//start of the nested loop

//outer loop iterates a number of times equal to the height of the arrow base

 for (int i = 0; i < arrowBaseHeight; i++) {

//inner loop prints the stars asterisks

      for (int j = 0; j <arrowBaseWidth; j++) {

          System.out.print("*");        } //displays stars

          System.out.println();          }

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for (int i = 1; i <= arrowHeadWidth; i++)

{     for(int j = k; j > 0; j--)     {//inner loop to print stars

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   System.out.println(); } } } // continues to add more asterisks for new line

Explanation:

The program asks to enter the height of the arrow base, width of the arrow base and the width of arrow head. When asking to enter the width of the arrow head, a condition is checked that the arrow head width arrowHeadWidth should be less than or equal to width of arrow base arrowBaseWidth. The while loop keeps iterating until the user enters the arrow head width larger than the value of arrow base width.

The loop is used to output an arrow base of height arrowBaseHeight. So point (1) is satisfied.

The nested loop is being used which as a whole outputs an arrow base of width arrowBaseWidth. The inner loop draws the stars and forms the base width of the arrow, and the outer loop iterates a number of times equal to the height of the arrow. So (2) is satisfied.

A temporary variable k is used to hold the original value of arrowHeadWidth so that it keeps safe when modification is done.

The last nested loop is used to output an arrow head of width arrowHeadWidth. The inner loop forms the arrow head and prints the stars needed to form an arrow head. So (3) is satisfied.

The value of temporary variable k is decreased by 1 so the next time it enters  the nested for loop it will be one asterisk lesser.

The screenshot of output is attached.

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