Question:
The following tabulated data were gathered from a series of Charpy impact tests on a commercial low-carbon steel alloy.
Temperature(∘C)50403020100-10-20-30-40Impact energy (J)76767158382314951.5
(a) Plot the data as impact energy versus temperature.
(b) Determine a ductile-to-brittle transition temperature as the temperature corresponding to the average of the maximum and minimum impact energies.
(c) Determine a ductile-to-brittle transition temperature as the temperature at which the impact energy is 20 J.
Answer:
a) see the attached graph
b) max E = 76 and Min E =1.53 average = 77.5/2 = 38.75 J
this corresponds to about 10° C
c ) at E = 20 J temperature is about -2°C
Answer:
The p-value of the hypothsis 0.00135
Explanation:
The answer is false. Square means a corner is a 90 degrees. Plumb means it vertically perpendicular to the surface.
Answer:
Hence wavelength of the photons produced by the laser is
Explanation:
Given
Efficiency of laser - 30%
As we know
h = plank's constant
c = speed of light
eV0 = band gap
Hence wavelength of the photons produced by the laser is
Answer:
a. 0.28
Explanation:
Given that
porosity =30%
hydraulic gradient = 0.0014
hydraulic conductivity = 6.9 x 10⁻4 m/s
We know that average linear velocity given as
The velocity in m/d ( 1 m/s =86400 m/d)
v= 0.27 m/d
So the nearest answer is 'a'.
a. 0.28