Question

A fluid at 300 K flows through a long, thin-walled pipe of 0.2-m diameter. The pipe is enclosed in a concrete casing that is of square cross section (1 m x 1 m). The axis of the pipe is centered in the casing. The outer surfaces of the casing are maintained at 500 K. Calculate the heat loss per 1m length of the pipe. Please make sure to follow the rules required for all homework assignments.

Answer 1

Answer:

The correct answer is "1341.288 W/m".

Explanation:

Given that:

T₁ = 300 K

T₂ = 500 K

Diameter,

d = 0.2 m

Length,

l = 1 m

As we know,

The shape factor will be:

⇒ $SF=\frac{2 \pi l}{ln[\frac{1.08 b }{d} ]}$

By putting the value, we get

⇒       $=\frac{2 \pi l}{ln[\frac{1.08\times 1}{0.2} ]}$

⇒       $=3.7258 \ l$

hence,

The heat loss will be:

⇒ $Q=SF\times K(T_2-T_1)$

       $=3.7258\times 1\times 1.8\times (500-300)$

       $=3.7258\times 1.8\times (200)$

       $=1341.288 \ W/m$