Answer:
See explanation
Explanation:
Solution:-
- Three students measure the volume of a liquid sample which is 6.321 L.
- Each student measured the liquid sample 4 times. The data is provided for each measurement taken by each student as follows:
Students
Trial A B C
1 6.35 6.31 6.38
2 6.32 6.31 6.32
3 6.33 6.32 6.36
4 6.36 6.35 6.36
- We will define the two terms stated in the question " precision " and "accuracy"
- Precision refers to how close the values are to the sample mean. The dense cluster of data is termed to be more precise. We will use the knowledge of statistics and determine the sample standard deviation for each student.
- The mean measurement taken by each student would be as follows:
- The precision can be quantize in terms of variance or standard deviation of data. Therefore, we will calculate the variance of each data:
- We will rank each student sample data in term sof precision by using the values of variance. The smallest spread or variance corresponds to highest precision. So we have:
Var ( A ) < Var ( B ) < Var ( C )
most precise Least precise
- Accuracy refers to how close the sample mean is to the actual data value. Where the actual volume of the liquid specimen was given to be 6.321 L. We will evaluate the percentage difference of sample values obtained by each student .
- Now we will rank the sample means values obtained by each student relative to the actual value of the volume of liquid specimen with the help of percentage difference calculated above. The least percentage difference corresponds to the highest accuracy as follows:
P ( B ) < P ( A ) < P ( C )
most accurate least accurate
The guy above me is right fyi and its not 50 points
Answer:
The GMAW process commonly uses a constant voltage power source (GMAW-CV) that allows for a relatively constant welding voltage output over a range of welding currents. For GMAW-CV the welder selects the wire feed speed (WFS) on the wire feeder unit and an appropriate voltage on the welding power supply.
complete question:
Put these expressions in a small program that will demonstrate whether they are true or false. Paste the code, and output from the program into your submission. Use if statements and output a message indicating that the expression is True or False.
a = 5, b = 4, c = 3, d = 2 ;
(a <= b + 1 )
(a < b && c > b)
(a >= c || d >= 5)
( !(a > b) )
( b >= a && ! (d < b) )
Answer:
a = 5
b = 4
c = 3
d = 2
if a <= b + 1 :
print("True")
else :
print("False")
if a < b and c > b :
print("True")
else :
print("False")
if a >= c or d >= 5:
print("True")
else :
print("False")
if not(a > b):
print("True")
else :
print("False")
if ( b >= a and not(d < b) ):
print("True")
else :
print("False")
Explanation:
I used python to write the code
The equivalent of && in python is and while the equivalent of || is or. The equivalent of ! is not in python .
I wrote an if statement to print True for each expression if it is actually true and the else statement print False if the expression is actually false.
For example the first expression says if a is less than or equal to b + 1(5). This statement is actually true so the expression will print True. a is 5 and b plus 1 is 5, so a is equal to 5 which is true.
if a < b and c > b :
Both expression must be true for the if statement to print True. a is not less than b and c is not greater than b so the expression amount to False.
if a >= c or d >= 5:
One expression must be true for the expression to be True. a >= c is true and d >= 5 is false. So the expression amount to True.
not(a > b)
This simply means negate the statement a > b . This gives False.
( b >= a and not(d < b))
b >= a is false
d < b is true
not(d < b) is false
false and false is definitely False