3 years ago

What is the completely factored form of p4 - 16?

Mathematics

2 answers:

dem82 [27]3 years ago

8 0

Answer:

see explanation

Step-by-step explanation:

Given

$p^{4}$ - 16 ← difference of 2 squares and factors in general as

a² - b² = (a - b)(a + b)

$p^{4}$ - 16

= (p² )² - 4²

= (p² - 4)(p² + 4) ← (p² - 4) is also a difference of squares

= (p - 2)(p + 2)(p² + 4)

Tanya [424]3 years ago

4 0

Answer:(p - 2)(p + 2)(p² + 4)

Step-by-step explanation:

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