Question

How do i fill out this ICE chart? please help

Answer 1

Answer : The given chemical reaction is:

                       $2C_6H_{10}+17O_2\rightarrow 12CO_2+10H_2O$

Initial            0.427          1.41         0             0

Change        -2x             -17x        +12x       +10x

Final         0.427-2x      1.41-17x    12x         10x

Explanation :

First we have to calculate the moles of $C_6H_{10}$ and $O_2$

$\text{Moles of }C_6H_{10}=\frac{\text{Mass of }C_6H_{10}}{\text{Molar mass of }C_6H_{10}}$

Mass of $C_6H_{10}$ = 35 g

Molar mass of $C_6H_{10}$ = 82 g/mol

$\text{Moles of }C_6H_{10}=\frac{35g}{82g/mol}=0.427mol$

and,

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}$

Mass of $O_2$ = 45 g

Molar mass of $O_2$ = 32 g/mol

$\text{Moles of }O_2=\frac{45g}{32g/mol}=1.41mol$

Now we have to complete the ICE table.

The given chemical reaction is:

                      $2C_6H_{10}+17O_2\rightarrow 12CO_2+10H_2O$

Initial             0.427          1.41        0             0

Change        -2x             -17x        +12x       +10x

Final         0.427-2x      1.41-17x      12x         10x

Answer 2

Answer: You can probably go onto You Tube and find that answer! Just be detailed in your search! Hope this helps!  

Explanation:

Just Simple Physics :P