Determine the standard enthalpy of formation in kJ/mol for NO given the following information about the formation of NO2 under s
1 answer:
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Answer:
0,0,0,0
Explanation:
The formal charge formula:
So:
Hydrogen: 1 elec. of valence and shares two electrons with the O
Oxygen: 6 elec. of valence, 2 lone pairs and shares two electrons with the H and two with the F
Fluorine: 7 elec. of valence, 6 lone pairs and shares two electrons with the O
Oxygen: 6 elec. of valence, 3 lone pairs
Note: the dative bond between F and the second O doesn't count as shared electrons.
Answer:
The kinetic energy of the two stones is 320 J
Explanation:
Kinetic energy is the energy that a body possesses due to its movement. So it is the capacity or work that allows an object to go from being at rest, or still, to moving at a certain speed.
In other words, the kinetic energy of an object is that which is produced due to its motion and depends on its mass and velocity as follows:
where the kinetic energy Ec is measured in joules (J), the mass m is measured in kilograms (kg) and the velocity v in meters/second (m/s).
In this case you know that a 20 kg curling stone is sliding in a positive direction at 4 m/s. So:
- m= 20 kg
- v= 4 m/s
Replacing you have:
Ec₁= 160 J
A second curling stone slides at the same speed but in the opposite direction. So:
- m= 20 kg
- v= - 4 m/s
Replacing you have:
Ec₂= 160 J
The kinetic energy of the two stones is calculated as:
Ec= Ec₁ + Ec₂
Ec= 160 J + 160 J
Ec= 320 J
<u><em>The kinetic energy of the two stones is 320 J</em></u>