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tester [92]
3 years ago
13

What is the area of the composite shape?

Mathematics
1 answer:
Lelu [443]3 years ago
3 0

Answer:

84 sq. inches

Step-by-step explanation:

When you section off each, you can find the area of each shape and add together to make composite.

Triangle on left is 6 sq. inches

Rectangle on right (5x10) is 50 sq. inches

Rectangle on bottom (7x4) is 28 sq. inches

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Equation for the given function
Lera25 [3.4K]

Answer:

Step-by-step explanation:

hello :

g(x) = (x+2)(x-4)/(x+2)(x-1)

1 )  this function no exist for if : x= -2 and 1

so the denominater is : (x+2)(x-1)

so : b= 2  and c=1

2) the x- intercept is : 4

so the numerater is : (x+2)(x-4)

g(x) =0 if : (x+2)(x-4)=0

means x-4=0    ...   (  x+2 ≠ 0)

note :

g(x) ≠ (x-4)/(x-1) except in the case  x ≠ -2  

7 0
3 years ago
Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat
zavuch27 [327]

Answer:

The equation contains exact roots at x = -4 and x = -1.

See attached image for the graph.

Step-by-step explanation:

We start by noticing that the expression on the left of the equal sign is a quadratic with leading term x^2, which means that its graph shows branches going up. Therefore:

1) if its vertex is ON the x axis, there would be one solution (root) to the equation.

2) if its vertex is below the x-axis, it is forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will not have real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently:

We recall that the x-position of the vertex for a quadratic function of the form f(x)=ax^2+bx+c is given by the expression: x_v=\frac{-b}{2a}

Since in our case a=1 and b=5, we get that the x-position of the vertex is: x_v=\frac{-b}{2a} \\x_v=\frac{-5}{2(1)}\\x_v=-\frac{5}{2}

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = -5/2:

y_v=f(-\frac{5}{2})\\y_v=(-\frac{5}{2} )^2+5(-\frac{5}{2} )+4\\y_v=\frac{25}{4} -\frac{25}{2} +4\\\\y_v=\frac{25}{4} -\frac{50}{4}+\frac{16}{4} \\y_v=-\frac{9}{4}

This is a negative value, which points us to the case in which there must be two real solutions to the equation (two x-axis crossings of the parabola's branches).

We can now continue plotting different parabola's points, by selecting x-values to the right and to the left of the x_v=-\frac{5}{2}. Like for example x = -2 and x = -1 (moving towards the right) , and x = -3 and x = -4 (moving towards the left.

When evaluating the function at these points, we notice that two of them render zero (which indicates they are the actual roots of the equation):

f(-1) = (-1)^2+5(-1)+4= 1-5+4 = 0\\f(-4)=(-4)^2+5(-4)_4=16-20+4=0

The actual graph we can complete with this info is shown in the image attached, where the actual roots (x-axis crossings) are pictured in red.

Then, the two roots are: x = -1 and x = -4.

5 0
3 years ago
jim is building a model of a square pyramid for a class project the side length of the square base is 12 inches and the slant he
yulyashka [42]
Surface area of a square pyramid is the area of the base + 4 times the area of one of the slanted sides.
Area of base = side length * side length
Area of side = (1/2) * side length * slant height
Don't forget that you have to multiply the area of the side by 4!

Step 1: 12 x 12 = 144
Step 2: 12 x 20 = 240 divided by 2 = 120
Step 3: 144 + 120 x 4
4 0
3 years ago
Read 2 more answers
Mariah025 answer here please
larisa [96]

Answer:

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4 0
3 years ago
Please help I need help on this thank you
Charra [1.4K]
IJ because I learned this
8 0
3 years ago
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