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3 years ago

Are the two displacements equal? Explain your answer.

Physics

2 answers:

Sergeu [11.5K]3 years ago

7 0

From the information given in the drawing, it's not possible
to tell whether the displacements are equal, because we
don't know what the vectors represent.

If the vectors are distances, then the displacements are not
equal, because the distance between the start and end points
are not equal.

If the vectors are speeds, then they don't tell us anything about
the distance between the start and end points, so we can't calculate
the displacements.

neonofarm [45]3 years ago

7 0

Answer:

The displacements are not equal. Their direction is the same but their length is not because A is longer than B.

Explanation:

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Three children are riding on the edge of a merry‑go‑round that has a mass of 105 kg105 kg and a radius of 1.80 m1.80 m . The mer

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Explanation:

In the given system the angular momentum of the system is conserved

initial angular momentum of the system

$L_{i}=I_{1}\omega _{1}\\\\\omega _{1}=\frac{8\pi }{15}rad/sec\\\\I_{1}=\frac{1}{2}mr^{2}+(m_{1}+m_{2}+m_{3})r^{2}\\\\I_{1}=\frac{1}{2}\times 105\times 1.8^{2}+(33+28+28) \times 1.8^{2}=458.46kgm^{2}\\\\\therefore L_{i}=458.46\times \frac{8\pi }{15}=768.16$

When 28 kg child moves to the center the moment of inertia changes thus we have

$I_{2}=\frac{1}{2}mr^{2}+(m_{1}+m_{2})r^{2}\\\\I_{1}=\frac{1}{2}\times 105\times 1.8^{2}+(33+28) \times 1.8^{2}=367.74kgm^{2}\\\\\therefore L_{f}=367.74\times \omega _{f}$

Equating initial and final angular momentum we get

$I_{2}=\frac{1}{2}mr^{2}+(m_{1}+m_{2})r^{2}\\\\I_{1}=\frac{1}{2}\times 105\times 1.8^{2}+(33+28) \times 1.8^{2}=367.74kgm^{2}\\\\\therefore L_{f}=367.74\times \omega _{f}\\\\\omega _{f}=\frac{768.16}{367.74}=2.1rad/sec\\\\N_{2}=19.95rpm$

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3 years ago