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grin007 [14]
3 years ago
8

Are the two displacements equal? Explain your answer.

Physics
2 answers:
Sergeu [11.5K]3 years ago
7 0
From the information given in the drawing, it's not possible
to tell whether the displacements are equal, because we
don't know what the vectors represent.

If the vectors are distances, then the displacements are not
equal, because the distance between the start and end points
are not equal.

If the vectors are speeds, then they don't tell us anything about
the distance between the start and end points, so we can't calculate
the displacements.
neonofarm [45]3 years ago
7 0

Answer:

The displacements are not equal. Their direction is the same but their length is not because  A is longer than B.

Explanation:

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Zigmanuir [339]
Radial acceleration is given by

a_{rad}= \frac{v^2}{r}
where 

v=r \omega
then

a_{rad}= \frac{r^2 \omega^2}{r}=r\omega^2

Now

70\omega^2=3.90 \frac{m}{s^2}  \\  \\ \omega= \sqrt{ \frac{3.9}{70} }

Using the relation

\omega=2 \pi f

2 \pi f= \sqrt{ \frac{3.9}{70} }\\  \\ f= \frac{1}{2 \pi}\sqrt{ \frac{3.9}{70} }Hz

Putting into rpm

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3 years ago
Two loudspeakers are placed next to each other and driven by the same source at 500 Hz. A listener is positioned in front of the
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To solve this problem we will apply the concepts related to wavelength as the rate of change of the speed of the wave over the frequency. Mathematically this is

\lambda = \frac{v}{f}

Here,

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f = Frequency,

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7 0
3 years ago
1-A train travels 100 km to reach town A in one hour and 15 min. The train stops at station A for 45 minutes. Then it travels 15
kirill [66]

Answer 1) : 62.5 km/hour is the average velocity of the train.

2) The final velocity of the car at the end of 75 m is 14.69 m/s

Explanation:

1) Displacement of the train = 100 km + 150 km = 250 km

Total time train took =1 hour 15 min+ 45 min + 2 hours = 240 min = 4 hours

Average velocity=\frac{Displacement}{time}=\frac{250 km}{4 hour}=62.5 km/h

62.5 km/hour is the average velocity of the train.

2) The acceleration of the car, a= 1.2 m/s^2

Distance covered by the car,s = 75 m

Initial velocity of the car ,v_i = 6 m/s

Final velocity of thre car ,v_f=?

Using third equation of motion:

v_{f}^2=v_{i}^2+2as=(6 m/s)^2+2\times 1.2 m/s\times 75 m=216 m^2/s^2

v_{f}=14.69 m/s

The final velocity of the car at the end of 75 m is 14.69 m/s

8 0
3 years ago
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