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Elina [12.6K]
2 years ago
7

In-------process the hot drawn bar or rod is pulled through the die.

Engineering
1 answer:
devlian [24]2 years ago
4 0

Answer:

Explanation:

he metallic rod is fixed into the dies by using a die holder and then a drawing head is used in which the metallic rod is fixed through a jaw mechanism. And then the bar is stretched and slides between the surfaces of the die

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Look at the data set below.
Goshia [24]
The answer would be 7
3 0
3 years ago
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12.28 LAB: Output values in a list below a user defined amount - functions Write a program that first gets a list of integers fr
Anastaziya [24]

Answer:

def output_ints_less_than_or_equal_to_threshold(user_values, upper_threshold):

   for value in user_values:

       if value < upper_threshold:

           print(value)  

def get_user_values():

   n = int(input())

   lst = []

   for i in range(n):

       lst.append(int(input()))

   return lst  

if __name__ == '__main__':

   userValues = get_user_values()

   upperThreshold = int(input())

   output_ints_less_than_or_equal_to_threshold(userValues, upperThreshold)

8 0
3 years ago
A heat engine that receives heat from a furnace at 1200°C and rejects waste heat to a river at 20°C has a thermal efficiency of
viktelen [127]

Answer:

second-law efficiency  = 62.42 %

Explanation:

given data

temperature T1 = 1200°C = 1473 K

temperature T2 = 20°C  =  293 K

thermal efficiency η = 50 percent

solution

as we know that thermal efficiency of reversible heat engine between same  temp reservoir

so here

efficiency ( reversible ) η1 = 1 - \frac{T2}{T1}      ............1

efficiency ( reversible ) η1  = 1 - \frac{293}{1473}  

so efficiency ( reversible ) η1  = 0.801

so here second-law efficiency of this power plant is

second-law efficiency = \frac{thernal\ efficiency}{0.801}

second-law efficiency = \frac{50}{0.801}  

second-law efficiency  = 62.42 %

3 0
3 years ago
Which investigative process is most helpful for learning about past societies?
tatuchka [14]

Answer: think it A

Explanation: makes

6 0
3 years ago
A coal fired power plant geneartes 2.4 lbs. of CO2 per kWh. A lighting system consumes 300,000kWh per year. A corporation is con
Serjik [45]

Answer:

The perceived economic impact of CO2 generated per year by lighting sstem is $8164.67.

Explanation:

The CO2 requirement for the plant is:

Amount of CO2 per year = (2.4 lb / KWh)(300,000 KWh)

Amount of CO2 per year = (720000 lb)(1 ton/ 2204.62 lb)

Amount of CO2 per year = 326.59 ton

The perceived economic impact of CO2 generated per year will then be:

Economic Impact = ($25 / ton)(326.59 ton)

<u>Economic Impact = $8164.67</u>

7 0
3 years ago
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