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jasenka [17]
3 years ago
8

Write a single statement that prints outsideTemperature with 2 digits in the fraction

Engineering
1 answer:
lord [1]3 years ago
3 0

Answer:

outsideTemperature=108.90

Explanation:

#include <iostream>

#include <ios>

#include <iomanip>

using namespace std;

int main()

{

double outsideTemperature = 108.90;

/* print outside temperature  */

cout << setprecision(2) << fixed << outsideTemperature << endl;  

return 0;

}

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Fittoniya [83]

Answer:

a.) -147V

b.) -120V

c.) 51V

Explanation:

a.) Equation for potential difference is the integral of the electrical field from a to b for the voltage V_ba = V(b)-V(a).

b.) The problem becomes easier to solve if you draw out the circuit. Since potential at Q is 0, then Q is at ground. So voltage across V_MQ is the same as potential at V_M.

c.) Same process as part b. Draw out the circuit and you'll see that the potential a point V_N is the same as the voltage across V_NP added with the 2V from the other box.

Honestly, these things take practice to get used to. It's really hard to explain this.

3 0
3 years ago
How much force is required if the ramp is 15 ft long
lord [1]

Answer:

do yah stiil need help

Explanation:

6 0
3 years ago
Water is pumped steadily through a 0.10-m diameter pipe from one closed pressurized tank to another tank. The pump adds 4.0 kW o
jekas [21]

Complete Question

Complete Question is attached below.

Answer:

V'=5m/s

Explanation:

From the question we are told that:

Diameter d=0.10m

Power P=4.0kW

Head loss \mu=10m

 \frac{P_1}{\rho g}+\frac{V_1^2}{2g}+Z_1+H_m=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}+Z_2+\mu

 \frac{300*10^3}{\rho g}+35+Hm=\frac{500*10^3}{\rho g}+15+10

 H_m=(\frac{200*10^3}{1000*9.8}-10)

 H_m=10.39m

Generally the equation for Power is mathematically given by

 P=\rho gQH_m

Therefore

 Q=\frac{P}{\rho g H_m}

 Q=\frac{4*10^4}{1000*9.81*10.9}

 Q=0.03935m^3/sec

Since

 Q=AV'

Where

 A=\pi r^2\\A=3.142 (0.05)^2

 A=7.85*10^{-3}

Therefore

 V'=\frac{0.03935m^3/sec}{7.85*10^{-3}}

 V'=5m/s

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3 years ago
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Setler79 [48]
Answer:

Thank you so much and may god bless you.
6 0
2 years ago
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PLEASE LOOK AT MY PROFILE AND IF YOU KNOW THE ANSWERS CAN YOU ANSWER THEM PLEASE. IM ON A TIMED ASSIGNMENT!!!!
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Answer:

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