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solmaris [256]
3 years ago
6

What type of eclipse is shown? How do you know?

Physics
2 answers:
Sonja [21]3 years ago
8 0
That is a lunar eclipse. At night, when the Earth is between the Sun and the moon, the moon would appear to be red. Just for future reference, a solar eclipse is when the Moon is between the Sun and Earth. Speaking of which, check out the solar eclipse this August!

Leno4ka [110]3 years ago
4 0

Answer:

Lunar bo

Explanation:

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A person pushes horizontally on a heavy box and slides it across the level floor at constant velocity. The person pushes with a
gogolik [260]

Answer:

W= 638.1 J

Explanation:

As we know that

Work done is the area of the force and displacement diagram.

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W=Work

F=force

dx=Elemental displacement

From the diagram ,area A

A= 60 x 7.09 + 1/2 x 60 x 7.09

A= 638.1 J

So the work W

W= 638.1 J

3 0
3 years ago
The uniform bar of mass m and length l is balanced in the vertical position when the horizontal force p is applied to the roller
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Which of the following is NOT a factor in efficiency?<span><span>A.metabolism</span><span>B.type of movement</span><span>C.muscle efficiency</span><span>D.digestion</span></span>
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3 years ago
If an airplane is flying directly north at 300.0 km/h, and a crosswind is hitting the airplane at 50.0 km/h from the east, what
Rashid [163]

Answer:

magnitude = 304.14 km/h

direction: 9.46^o West of North

Explanation:

The final plane's vector velocity will be the result of the vector addition of one pointing North of length 300 km/h, another one pointing West of length 50 km/h.

To find the magnitude of the final velocity vector (speed) we need to apply the Pythagorean theorem in a right angle triangle with sides: 300 and 50, and find its hypotenuse:

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The actual direction of the plane is calculated using trigonometry, in particular with the arctan function, since the tangent of the angle can be written as:

tan(\theta)=\frac{50}{300} = \frac{1}{6} \\\theta = arctan(\frac{1}{6} ) = 9.46^o

So the resultant velocity vector of the plane has magnitude = 304.14 km/h,

and it points 9.46^o West of the North direction.

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What's a good way to determine the net force of something
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By adding up all the individual forces of the object
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Copernicus incorrectly assumed that the planets?
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Nicholas Copernicus correctly assumed that the planets revolved around the sun but he incorrectly assumed that the planets followed a perfect circle orbit around the sun. It was later on discovered by Johannes Kepler that the planets moved around the sun following an elliptical orbit.
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