All categories

3 years ago

A car accelerates from rest at a rate of 4 m/s’2 . How many seconds will it take the car to reach a final speed of 16m/s

Physics

1 answer:

RSB [31]3 years ago

6 0

Answer:

t = 4 [s]

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f}=v_{o}+a*t$

where:

Vf = final velocity = 16 [m/s]

Vo = initial velocity = 0

a = acceleration = 4 [m/s²]

t = time [s]

Now replacing:

$16=0+4*t\\t = 16/4\\t = 4[s]$

You might be interested in

In order to be a good conductor, a martial needs to...

Travka [436]

B-allow electrons to flow

8 0

3 years ago

A string of length L, mass per unit length \mu, and tension T is vibrating at its fundamental frequency. What effect will the fo

viva [34]

The fundamental frequency on a vibrating string is given by:

$f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}$

where

L is the length of the string

T is the tension

$\mu$ is the mass per unit length of the string

Keeping this equation in mind, we can now answer the various parts of the question:

(a) The fundamental frequency will halve

In this case, the length of the string is doubled:

L' = 2L

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2(2L)}\sqrt{\frac{T}{\mu}}=\frac{1}{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{2}$

So, the fundamental frequency will halve.

(b) the fundamental frequency will decrease by a factor $\sqrt{2}$

In this case, the mass per unit length is doubled:

$\mu'=2\mu$

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2L}\sqrt{\frac{T}{2 \mu}}=\frac{1}{\sqrt{2}}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{\sqrt{2}}$

So, the fundamental frequency will decrease by a factor $\sqrt{2}$ .

(c) the fundamental frequency will increase by a factor $\sqrt{2}$

In this case, the tension is doubled:

$T'=2T$

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2L}\sqrt{\frac{2T}{\mu}}=\sqrt{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\sqrt{2}f$

So, the fundamental frequency will increase by a factor $\sqrt{2}$ .

8 0

3 years ago

A 25 kg lamp is hanging from a rope. What is the tension force being supplied by the rope?

d1i1m1o1n [39]

The tension force being supplied by the rope is 245 N.

<h3>What is tension force?</h3>

Tension force is the force exerted on a rope or cord due to the weight of an object suspended from it.

The tension force on the given rope due to the weight of the lamp hanging from the rope is calculated by applying Newton's second law of motion as shown below;

T = mg

where;

m is the mass = 25 kg
g is acceleration due to gravity = 9.8 m/s²

T = 25 x 9.8

T = 245 N

Thus, the tension force being supplied by the rope is 245 N.

Learn more about tension force here: brainly.com/question/2008782

4 0

2 years ago

When was the first airplane made?

expeople1 [14]

The first ariplanr was made December 17, 1903

3 0

4 years ago

Read 2 more answers

A student constructs a simple constant volume gas thermometer and calibrates it using the boiling point of water, 100°C, and the

just olya [345]

Answer:

The pressure corresponding to the absolute zero temperature is 0.997atm.

Explanation:

To solve this question, you draw a straight vertical line with the boiling point temperature and pressure on top of the line and the freezing point temperature and pressure on the lower part. The absolute temperature somewhere in the middle of the line with the pressure to be obtained.

So, we have;

0- (-19) / 100 - (-19) = P - 0.9267 / 1.366 - 0.9267

19 / 119 = P - 0.9267 / 0.4393

Cross multiply, we have

19 * 0.4393 = 119(P -0.9267)

8.3467 = 119P - 110.2773

119P = 118.624

P = 0.997 atm

So at 0°C, the pressure of the thermometer is 0.997atm.

4 0

3 years ago