The work done by the engine is converted into kinetic energy of the motorbike+rider system:
![W=K=\frac{1}{2}mv^2](https://tex.z-dn.net/?f=%20W%3DK%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%20)
where
W=6400 J is the work
m=200 kg is the mass of the system
v is the speed acquired by the motorbike
Rearranging the equation and substituting the numbers in, we find
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Answer:
![y = 104.4 ft](https://tex.z-dn.net/?f=y%20%3D%20104.4%20ft)
Explanation:
As we know that we board in the car of ferris wheel at the bottom position
So we will have
final height of the car at angular displacement given as
![y = y_o + R + R sin(270 - 255)](https://tex.z-dn.net/?f=y%20%3D%20y_o%20%2B%20R%20%2B%20R%20sin%28270%20-%20255%29)
![y = y_o + R + R sin 15](https://tex.z-dn.net/?f=y%20%3D%20y_o%20%2B%20R%20%2B%20R%20sin%2015)
here we know that
![y_o = 10 ft](https://tex.z-dn.net/?f=y_o%20%3D%2010%20ft)
![R = 75 ft](https://tex.z-dn.net/?f=R%20%3D%2075%20ft)
so we have
![y = 10 + 75 + 75 sin15](https://tex.z-dn.net/?f=y%20%3D%2010%20%2B%2075%20%2B%2075%20sin15)
![y = 104.4 ft](https://tex.z-dn.net/?f=y%20%3D%20104.4%20ft)
Answer:
Work done.
Explanation:
The skater who lifts has to overcome the partner's weight. When lifted up by 1 meter, her potential energy increases by (mass)x(gravitational acceleration)x(1meter), which is the amount of work done.
(This all assumes lifting vertically and no other forces being part of the picture)
This Is What I Found<span>(Non-electric stoves and ovens use gas energy, a chemical energy. This is then transformed into heat.) What types of energy does a computer convert electricity into? (Light, sound, motion, and heat.) I'm Not Taking Credit For It, Because I Didn't Come Up With That Answer.</span>