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3 years ago

Which of the following is an example of ionic compound?

1 answer:

5 0

What you are looking for is something from the left side of the periodic table (the metals), combined with something from the right side of the periodic table.

SiCl4 is something from the middle with something on the right. Not the answer.

HCl is a possible answer, but it is not the best one, because Hydrogen can be on both sides. It is not quite as willing to give up its electrons as the answer.

CCl4 has the same problem as A.

The answer is C

Ca is in column 2 just about as far left as you can get.

Cl is in column 17 which is just about as far right as you can get.

You might be interested in

What is the oxidation number of cl− in the perchlorate ion

Yuri [45]

Answer:

The answer is: +7

Explanation:

Oxidation state or oxidation number of an element is the hypothetical charge on an element that forms completely ionic bonds. The oxidation number represents the number of electrons lost or gained by that element.

Perchlorate ion is a molecule with a chemical formula: ClO₄⁻

The oxidation state of oxygen in ClO₄⁻ = -2,

the total charge on the ClO₄⁻ molecule = -1,

let the oxidation state of chlorine be x

As the sum of oxidation states of all elements in a molecule is equal to the total charge on the molecule.

⇒ oxidation state of chlorine + oxidation state of oxygen × 4 = total charge on the molecule

⇒ x + (-2) × 4 = -1

⇒ x + (-8) = -1

⇒ x = -1 + 8 = +7

⇒ x = +7

Therefore, the oxidation state of chlorine in the perchlorate ion (ClO₄⁻): x = +7

5 0

3 years ago

Which of the following elements has the greatest atomic radius? Al S Si C

suter [353]

Answer:

The answer to your question is: Al, Si have the greatest and S, C have the smallest.

Explanation:

Atomic radius increases from right to left in the periodic table.

Atomic radius increases from the upper section to the lower section of the periodic table.

Order of the atomic radius from highest to lowest.

Al, Si, S and C

6 0

3 years ago

Which of the following chemical substances has a triple

Otrada [13]

Answer:

c. carbon monoxide

Explanation:

no one bothers to read why anyways so look at the picture

3 0

3 years ago

What types of emergency situations could rescue workers be in that would make it difficult for them to get energy to their elect

artcher [175]

Answer:

Large-scale natural disasters

Explanation:

The emergency situation that rescue workers could be in that would make it difficult for them to get energy to their electrical devices is "Large-scale natural disasters"

Large-scale natural disasters are very destructive and devastating. Their impact and effect can range from destruction of infrastructures, properties, social amenities and even ecosystems. When such disasters break out, they destroy things and which leads to difficulty in accessing certain amenities. Rescue workers even find it difficult to access energy for their electrical devices - because there is power outage.

Some of these large-scale natural disasters are earthquakes, tornadoes, hurricanes, floods, etc.

4 0

3 years ago

A solution was prepared by dissolving 0.800 g of sulfur S8, in 100.0 g of acetic acid, HC2H3O2. Calculate the freezing point and

sammy [17]

Answer: The freezing point of solution is 16.5°C and the boiling point of solution is 118.2°C

Explanation:

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute $(S_8)$ = 0.800 g

$M_{solute}$ = Molar mass of solute $(S-8)$ = 256.52 g/mol

$W_{solvent}$ = Mass of solvent (acetic acid) = 100.0 g

Putting values in above equation, we get:

$\text{Molality of solution}=\frac{0.800\times 1000}{256.52\times 100.0}\\\\\text{Molality of solution}=0.0312m$

Calculation for freezing point of solution:

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

$\Delta T_f=\text{freezing point of acetic acid}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

or,

$\text{Freezing point of acetic acid}-\text{Freezing point of solution}=iK_fm$

where,

Freezing point of acetic acid = 16.6°C

i = Vant hoff factor = 1 (for non-electrolyte)

$K_f$ = molal freezing point depression constant = 3.59°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

$16.6^oC-\text{freezing point of solution}=1\times 3.59^oC/m\times 0.0312m\\\\\text{Freezing point of solution}=16.5^oC$

Hence, the freezing point of solution is 16.5°C

Calculation for boiling point of solution:

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of acetic acid}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

or,

$\text{Boiling point of solution}-\text{Boiling point of acetic acid}=iK_fm$

where,

Boiling point of acetic acid = 118.1°C

i = Vant hoff factor = 1 (for non-electrolyte)

$K_f$ = molal boiling point elevation constant = 3.08°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

$\text{Boiling point of solution}-118.1^oC=1\times 3.08^oC/m\times 0.0312m\\\\\text{Boiling point of solution}=118.2^oC$

Hence, the boiling point of solution is 118.2°C

5 0

3 years ago