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Leokris [45]
3 years ago
7

A ball is pushed down a hill so that it starts with a velocity of 2.0 m/s. It accelerates at a rate of 0.50 m/s2 for the length

of the hill, 10.0 m. What is the velocity of the ball at the bottom of the hill?
Physics
1 answer:
Delicious77 [7]3 years ago
7 0

Answer:

3.7 m/s

Explanation:

Given:

Δx = 10.0 m

v₀ = 2.0 m/s

a = 0.50 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (2.0 m/s)² + 2 (0.50 m/s²) (10.0 m)

v = 3.7 m/s

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A 100-kg block being released from rest from a height of 1.0 m. It then takes it 1.40 s to reach the floor. What is the mass m o
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Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass of the other block is  m_1 = 81.14 \ kg

Explanation:

From the question we are told that

   Mass of the first block is  m_1 = 100 \  kg

   The height is  s =  1.0 \  m

   The time it takes it is  t = 1.40 \  s

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Generally from the diagram the resultant force due to the weight of the first object and the tension on the string is  mathematically represented as

      mg - T = ma

=>   T  =  m g - ma

=>   T  =  m(g - a)

=>   T  =  877.96 \  N

Generally from the diagram the resultant force due to the weight of the second object and the tension on the string is  mathematically represented as  

     T - m_1g  =  m_1 a

=>   877.96  =  m_1 (a + g)

=>   877.96  =  m_1 (1.0204  + 9.8 )

=>   m_1 = 81.14 \ kg

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