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motikmotik
3 years ago
11

A solution of cough syrup contains 5.00% active ingredient by volume. if the total volume of the bottle is 51.0 ml , how many mi

lliliters of active ingredient are in the bottle?
Chemistry
1 answer:
amm18123 years ago
3 0
<span>The total volume of the bottle is 51.0ml and the active ingredient is 5.00% by volume then multipy 0.05 x 51.0 = 2.55 ml of active ingredient. Being 5% by volume means that of the total 51.0 ml, 5% of it is active ingredient and the balance is inactive or may even be water. </span>
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Calculate the mass, in grams, of a single xenon atom (mxe = 131.29 amu ).
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Answer is 2.18017\times10^{-22}gms.

Explanation: To calculate the mass of 1 Xe-atom , we will require atomic mass of Xe which is 131.29amu.

This atomic mass is the mass of 1 mole of 1 Xe-atom. One mole of Xe-atom is 6.022\times10^{23} atoms of Xe. We will use this relation to convert Mass of Xe-atom into grams.

\frac{\text{mass of 1 atom}}{atom}=\frac{\text{mass of 1 mole of atom}}{6.022\times10^{23}atoms}

\text{mass of 1 atom}=\frac{\text{mass of 1 mole of atom}}{6.022\times10^{23}}

\text{mass of 1 Xe-atom}=\frac{131.29}{6.022\times10^{23}}

\text{mass of 1-Xe atom}=21.8017\times10^{-23}gms

                                               =2.18017\times10^{-22}gms


5 0
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Which method would increase the solubility of a gas?
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Temperature and Pressure One way to increase the solubility of a gas is to decrease the temperature of the liquid.  The solubility of a gas in a liquid is usually temperature dependent, although it depends on the particular combination of which gas and which liquid.  Usually the solubility of a gas goes down with increasing temperature (think of warm carbonated beverages going flat). 

<span>The other way to increase the solubility is to increase the pressure of the gas.  The higher the pressure of the gas above the liquid, the more will dissolve.  Again, think of a carbonated beverage:  when it is sealed it doesn't go flat because it is under pressure, but when open to air, it will go flat. </span>
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