Answer:
Heating is the best method
Explanation:
When a mass of crystals containing Water of crystallization is heated sufiiciently to a high temperature, water vapor may be driven off the crystals by the action of heat alone.
Given:
pH is 5.27
Concentration of sol'n 0.013m (weak monoprotic)
Determine H+ concentration:
[H+] = 10^-pH
= 10^-5.27
= 5.37x10^-6
Ka = [H+] [A-] / [HA]
= (5.37x10^-6) * (5.37x10^-6) / (0.013 - 5.37x10^-6)
= 2.22x10^-9
From the information provided in the question, the mass of gold that can be obtained from this sample is 31.5 g of Au.
Given that the reduction of gold III occurs thus;
Au^3+(aq) + 3e ------> Au(s)
Number of moles of gold(III) chloride dihydrate = mass/molar mass = 54.9 g /339.35 g/mol = 0.16 moles
Number of moles of Au^3+ in AuCl3.2H20 = 0.16 moles
Now;
1 mole of Au has a mass of 197 g/mol
0.16 moles of Au has a mass of 0.16 moles × 197 g/mol/1 mole
= 31.5 g of Au.
The mass of gold that can be obtained from this sample is 31.5 g of Au.
Learn more: brainly.com/question/6284546
Answer:
OptionA. 2C4H10 + 13O2 —> 8CO2 + 10H20
Explanation:
Butane burns is air (O2) according to the equation:
C4H10 + O2 —> CO2 + H20
Considering the equation, it is evident that it not balanced. Now let us balance the equation as shown below;
There are a total of 4 carbon atoms on the left and 1 carbon atom on the right. It can be balanced by putting 4 in front of CO2 as shown below:
C4H10 + O2 —> 4CO2 + H20
Next, there are 10 hydrogen atoms on the left and 2 hydrogen atoms on the right. Therefore to balance it, put 5 in front of H2O as shown below:
C4H10 + O2 —> 4CO2 + 5H20
Now, there are a total of 13 oxygen atoms on the right and 2 at the left. To balance it, put 13/2 in front of O2
as shown below
C4H10 + 13/2O2 —> 4CO2 + 5H20
Now we multiply through by 2 clear off the fraction and we obtained:
2C4H10 + 13O2 —> 8CO2 + 10H20