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3 years ago

The energy received by Earth from the sun is what type of energy

Chemistry

2 answers:

Snowcat [4.5K]3 years ago

6 0

Answer:

Solar Energy

Explanation:

DedPeter [7]3 years ago

3 0

Answer:

Solar Energy

Explanation:

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What is the Domain with four kingdoms or organisms that have cells with nuclei?

blondinia [14]

Wym kingdom? I dont get it

3 0

3 years ago

Which of the following is ONE of the signs of a chemical change

pickupchik [31]

Answer:

um i one of what?

Explanation:

6 0

3 years ago

Read 2 more answers

A sailor on a trans-Pacific solo voyage notices one day that if he puts 735.mL of fresh water into a plastic cup weighing 25.0g,

Gennadij [26K]

Answer:

Amount of salt in 1 L seawater = 34 g

Explanation:

According to Archimedes' principle, mass of freshwater and cup = mass of equal volume of seawater

mass of freshwater = density * volume

1 cm³ = 1 mL

mass of freshwater = 0.999 g/cm³ * 735 cm³ = 734.265 g

mass of freshwater + cup = 734.265 + 25 = 759.265 g

Therefore, mass of equal volume of seawater = 759.265 g

Volume of seawater displaced = 735 mL = 0.735 L (assuming the cup volume is negligible)

1 liter = 1000 cm³ = 1000 mL;

Density of seawater = mass / volume

Density of seawater = 759.265 g / 0.735 L = 1033.01 g/L

Density of freshwater in g/L = 0.999 g/ (1/1000) L = 999 g/L

mass of 1 Liter seawater = 1033.01 g

mass of 1 Liter freshwater = 999 g

mass of salt dissolved in 1 L of seawater = 1033.01 g - 999 g = 34.01 g

Therefore, amount of salt in 1 L seawater = 34 g

4 0

3 years ago

The balanced chemical equation for the reaction between sodium chloride and silver nitrate is:

bonufazy [111]

Answer:

We can Interprete it as 1mole of Sodium Chloride and 1mole of Silver Nitrate React to Produce

1Mole of Silver Chloride and 1Mole of Sodium Nitrate

7 0

2 years ago

Read 2 more answers

1826.5g of methanol (CH3OH), molar mass = 32.0 g/mol is added to 735 g of water, what is the molality of the methane 0.0348 m 1.

Snowcat [4.5K]

Answer:

Molality = 1.13 m

Explanation:

Molality is defined as the moles of the solute present in 1 kilogram of the solvent.

Given that:

Mass of $CH_3OH$ = 26.5 g

Molar mass of $CH_3OH$ = 32.04 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{26.5\ g}{32.04\ g/mol}$

$Moles\ of\ CH_3OH= 0.8271\ moles$

Mass of water = 735 g = 0.735 kg ( 1 g = 0.001 kg )

So, molality is:

$m=\frac {0.8271\ moles}{0.735\ kg}$

<u>Molality = 1.13 m</u>

4 0

3 years ago