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yaroslaw [1]
3 years ago
7

Janice has just measured the density of an object. Which value is possible? (Density: D = )

Physics
2 answers:
horsena [70]3 years ago
8 0

By definition, the density of an object is given by:

D = \frac{M}{V}

Where,

M: mass of the object

V: volume of the object

Since the mass and volume of an object are numerical values greater than zero, then it follows that:

D> 0

It is important to respect the units of each measure.

For this case we can use the grams for the mass and cubic centimeters for the volume.

Answer:

A possible value for density is given by:

6 \frac{g}{cm^3}

Sunny_sXe [5.5K]3 years ago
7 0

By definition, the density of an object is given by:

D = \frac{M}{V}

Where,

M: mass of the object

V: volume of the object

Since the mass and volume of an object are numerical values greater than zero, then it follows that:

D> 0

It is important to respect the units of each measure.

For this case we can use the grams for the mass and cubic centimeters for the volume.

Answer:

A possible value for density is given by:

6 \frac{g}{cm^3}

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Answer:

D

Explanation

take 5x2000 and J is the unit for power therfore it cant be A and B and C are not 10,000.

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3 years ago
In the diagram, q1 and q2 are both +5.00*10^-8 C. What is the electric field at point P? Include a + or - sign to indicate the d
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1389.1

Explanation:

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2 years ago
What is the Kinetic Energy of a 60 kg person on skis traveling 20 m/s?
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Explanation:

equating the parameters into the formula, it's gonna be

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3 years ago
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djverab [1.8K]
I think the correct answer is C
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3 years ago
vA 61.2-kg circus performer is fired from a cannon that is elevated at an angle of 57.8 ° above the horizontal. The cannon uses
dsp73

Answer:

The effective spring constant of the firing mechanism is 1808N/m.

Explanation:

First, we can use kinematics to obtain the initial velocity of the performer. Since we know the angle at which he was launched, the horizontal distance and the time in which it's traveled, we can calculate the speed by:

v_0_x=\frac{x}{t}\\ \\v_0\cos\theta=\frac{x}{t}\\\\v_0=\frac{x}{t\cos\theta}

(This is correct because the horizontal motion has acceleration zero). Then:

v_0=\frac{20.8m}{(2.60s)\cos57.8\°}\\\\v_0=15.0m/s

Now, we can use energy to obtain the spring constant of the firing mechanism. By the conservation of mechanical energy, considering the instant in which the elastic band is at its maximum stretch as t=0, and the instant in which the performer flies free of the bands as final time, we have:

E_0=E_f\\\\U_e=K\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\\implies k=\frac{mv^2}{x^2}

Then, plugging in the given values, we obtain:

k=\frac{(61.2kg)(15.0m/s)^2}{(2.76m)^2}\\\\k=1808N/m

Finally, the effective spring constant of the firing mechanism is 1808N/m.

3 0
3 years ago
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