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Marat540 [252]
3 years ago
6

What do astronomers mean by light pollution?

Physics
1 answer:
Komok [63]3 years ago
7 0
Light pollution is influence of the light on earth (for example, street lighting) which interrupt observations. For example, if you are in a street during the night and street lights are turned on you won't see stars, but if lighting is turned off or if you go out of town you will see stars above.
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What are things that we can do to protect our climate for future generations?
Vilka [71]
<span>Reduce energy use.
Change the way you think about transportation. Walk or bike whenever possible.
Insulate your home. Insulate yourself and your home.
Make every drop count. 
</span>Cool wash and hang to dry.
<span>Switch to "green power.
</span>Recycle.
6 0
3 years ago
Select the statement that is not true about the Hubble Telescope:
xxMikexx [17]

Answer:

The option is B is not true for Hubble telescope.

4 0
3 years ago
Question 18 according to newton's second law of motion, the force acting on an object varies directly with the object's accelera
leonid [27]
Solve for "x"
X=force
18/6=x/9
cross multiply 
162=6x
x=27
Hope this helps
3 0
3 years ago
An engine absorbs 1749 J from a hot reservoir and expels 539 J to a cold reservoir in each cycle. a. What is the engine’s effici
Masja [62]

Answer:

a)η = 69.18 %

b)W= 1210 J

c)P=3967.21 W

Explanation:

Given that

Q₁ = 1749 J

Q₂ = 539  J

From first law of thermodynamics

Q₁   = Q₂ +W

W=Work out put

Q₂=Heat rejected to the cold reservoir

Q₁ =heat absorb by hot  reservoir

W= Q₁- Q₂

W= 1210 J

The efficiency given as

\eta=\dfrac{W}{Q_1}

\eta=\dfrac{1210}{1749}

\eta=0.6918

η = 69.18 %

We know that rate of work done is known as power

P=\dfrac{W}{t}

P=\dfrac{1210}{0.305}\ W

P=3967.21 W

8 0
3 years ago
The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 23
Burka [1]

Answer:

a) v(2) = 3.9\,\frac{m}{s}, b) v(4) = -15.7\,\frac{m}{s}

Explanation:

a) The equation for vertical velocity is obtained by deriving the function with respect to time:

v(t) = 23.5 -9.8\cdot t

The velocities at given instants are, respectivelly:

v(2) = 3.9\,\frac{m}{s}

v(4) = -15.7\,\frac{m}{s}

8 0
3 years ago
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