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kotykmax [81]
3 years ago
12

A farmer needs to fence a rectangular piece of land.She wants the length of the field to be 55 feet longer than the width. If sh

e has 1310 feet of fencing material, what should be the length and the width of the field?
Mathematics
1 answer:
myrzilka [38]3 years ago
6 0
Call the width ' W '.
Then the length is W + 55

Perimeter (distance all around) = W + (W+55) + W + (W+55) = 4W + 110

4W + 110 = 1,310

4W = 1,200

W = 300-ft

Length = W + 55 = 355-ft
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Factor by Grouping.
Komok [63]

Answer:

The ac product of 35x^2+41x+12 is <u>420</u>.

The factors of the ac product that add to 41 are <u>20</u> and <u>21</u>.

35x^2+41x+12 = (7x+4)(5x+3)

Step-by-step explanation:

1) The general form of a quadratic is ax^2 + bx + c. Hence, multiplying 35 by 12 gives you the product of ac, which is 420.

2) We need to find two numbers that multiply to 420 and add up to 41 <u>simultaneously</u>. If we pull out the factors of 420, two of them will be 20 and 21, which multiply to 420 as well as add up to 41.

3) Write 41x as a sum.

35x^2+20x+21x+12

Now, we can factor them out by grouping.

35x^2+20x+21x+12\\5x(7x+4)+3(7x+4)

Since, 7x +4 is common in both of the factors, we only take one of the 7x+4 along with 5x and 3.

(7x+4)(5x+3)

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2 years ago
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Ima be honest I used a calculator but the answer is 82
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Round to the nearest hundredth
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Answer: 0.14

Step-by-step explanation:

5 / (25+5+5)

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3 years ago
A bank is reviewing its risk management policies with regards to mortgages. To minimize the risk of lending, the bank wants to c
Mariana [72]

Answer:

1. $ \mu = \$306,500 $

2. \sigma = \$24,500

3. n = 150

4. $ \mu_{x}= \mu = \$306,500 $

5. \sigma_x = \$ 2,000 \\\\

Step-by-step explanation:

The average mortgage owed by Americans is $306,500, with a standard deviation of $24,500.

From the above information, we know that,  

The population mean is

$ \mu = \$306,500 $

The population standard deviation is

\sigma = \$24,500

Suppose a random sample of 150 Americans is selected

n = 150

Since the sample size is quite large then according to the central limit theorem, the sample mean is approximately normally distributed.

The sample mean would be the same as the population mean  that is

$ \mu_{x}= \mu = \$306,500 $

The sample standard deviation is given by

\sigma_x = \frac{\sigma}{\sqrt{n} }

Where \sigma is the population standard deviation and n is the sample size.

\sigma_x = \frac{24,500}{\sqrt{150} }  \\\\\sigma_x = \$ 2,000 \\\\

Therefore, the required parameters are:

1. $ \mu = \$306,500 $

2. \sigma = \$24,500

3. n = 150

4. $ \mu_{x}= \mu = \$306,500 $

5. \sigma_x = \$ 2,000 \\\\

5 0
3 years ago
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