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svp [43]
2 years ago
8

A chemistry student needs 55.0g of carbon tetrachloride for an experiment. by consulting the crc handbook of chemistry and physi

cs, the student discovers that the density of carbon tetrachloride is 1.59·gcm−3 . calculate the volume of carbon tetrachloride the student should pour out.
Chemistry
1 answer:
Monica [59]2 years ago
6 0

The volume of a substance is simply the ratio of mass and density. Therefore:

volume = mass / density

 

Calculating for volume of Carbon Tetrachloride that the student has to pour out:

volume = 55.0 g / (1.59 g / cm^3)

<span>volume = 34.60 cm^3</span>

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5 0
3 years ago
Phosphine, PH₃, is a colorless, toxic gas that is used in the production of semiconductors as well as in the farming industry. W
Vilka [71]

Answer:

0.57 atm

Explanation:

Anytime a reaction is of the first order, the integrated law states that

ln[A]t/[A]₀ = - kt

where [A]t is the concentration of A ( phosphine in this question ) after a time, t

          [A]₀ is the initial concentration of A (phosphine also)

          k is a constant,

          t is the time

We also know that for a first order reaction,

          half life is t1/2 =0.693/k, then, k= 0.693/ t 1/2

where t 1/2 is the half-life.

This equation is derived for a situation when A]t/= 1/2 x [A]₀ which occurs at the half-life.

Thus, finding k from the half life time, and then solving it for a time t = 70.5 s

k = 0.693 /  35.0 s = 0.0198 s⁻¹

ln [ PH₃ ]t / [ PH₃]₀ = - kt

from ideal gas law we know that pV = nRT, so the volumes  will cancel:

ln (pPH₃ )t / p(PH₃)₀ = - kt

taking inverse log to both sides of the equation:

(pPH₃ )t / p(PH₃)₀  = - kt

then

(pPH₃ )t  = 2.29 atm x e^(- 0.0198 s⁻¹ x 70.5 s ) = 0.57 atm

4 0
2 years ago
Which pair of properties describes the elements in Group 18?
olga55 [171]

Answer

-12

Explanation:

Cs 22 is not close to -12

6 0
3 years ago
What are 4 other gases in the atmosphere besides oxegen and nitergin?
Levart [38]
Helium, neon,nitrogen and argon
5 0
2 years ago
what is the volume of the air in a balloon that occupies 0.730 L at 28.0 c if the temperature is lowered to 0.00 C
svetoff [14.1K]

Answer:

The volume of the air is 0.662 L

Explanation:

Charles's Law is a gas law that relates the volume and temperature of a certain amount of gas at constant pressure. This law says that for a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement they have. the gas molecules. This is represented by the quotient that exists between volume and temperature will always have the same value:

\frac{V}{T}=k

If you have a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment and several the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:

\frac{V1}{T1}=\frac{V2}{T2}

In this case:

  • V1= 0.730 L
  • T1= 28 °C= 301 °K (0°C= 273°K)
  • V2= ?
  • T2= 0°C= 273 °K

Replacing:

\frac{0.730 L}{301K}=\frac{V2}{273K}

Solving:

V2=273K*\frac{0.730L}{301K}

V2=0.662 L

<u><em>The volume of the air is 0.662 L</em></u>

6 0
3 years ago
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