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cluponka [151]
3 years ago
10

What solute particles are present in an aqueous solution of CH3COCH3?

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
4 0
PE, GO, XY - I am  probably wrong xoxoxoxoxxo
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Explain how acid–base indicators can be used to determine the approximate pH of a substance.
mezya [45]
PH stands for potential hydrogen.
pH can be accurately tested using acid-based indicators since it is a part of the pH of something itself. (acid and bases) The indicators themselves work when the acidic properties of the indicator begins to dissolve and form ions which gives the color indicating the pH.


5 0
3 years ago
Describe how to find the area of a triangle (do not just give the formula)
NemiM [27]
When you have the bottom measurement of the triangle (base) and the height of the triangle in the center, you multiply them together and then divide by 2.

~Do you need more explaining~?

8 0
3 years ago
which statement best describes a mole? it is 12 units of a given substance. it contains 6.02 1023 grams of sodium chloride. it i
Digiron [165]

Answer:

The correct option is;

It contains 6.02 × 10²³ particles of a given substance

Explanation:

A mole of substance is the standard scientific unit of measurement for the quantity of the substance which is made up of a large number of small particles such as molecules, ions, atoms, electrons or other entities.

The General Conference on Weights and Measures defines the mole as the amount of a substance that contains 6.02214076 × 10²³ units of entities

The number 6.02214076 × 10²³, is also known as Avogadro's number.

4 0
3 years ago
Read 2 more answers
How many molecules of co2 in 97.3 grams of co2
s2008m [1.1K]

Answer:

1.33 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Stoichiometry</u>

  • Reading a Periodic Table
  • Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

97.3 g CO₂

<u>Step 2: Define conversions</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

97.3 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.33138 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

1.33138 × 10²⁴ molecules CO₂ ≈ 1.33 × 10²⁴ molecules CO₂

8 0
3 years ago
Ionization and electronegativity are related to the periodic table in that:
Alla [95]
The answer would be A.
5 0
3 years ago
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