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Vilka [71]
3 years ago
7

How many feet are in 6.75 miles? (6.75x1) divided by 5280 =

Chemistry
1 answer:
disa [49]3 years ago
7 0

Answer:

0.00127840909

Explanation:

yehehdhdalakdjhd

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Why was it important to establish the Clean Air Act?
frosja888 [35]

Answer:

It was important to establish the clean air act to create a regulation that makes any activities pollute the air illegal

Explanation:

8 0
3 years ago
Read 2 more answers
What mass of sodium bromide would be needed to form a saturated solution in 25 g of water at 300K? The solubility of sodium brom
HACTEHA [7]

Answer:

irhnckdhsbj

Explanation:

iidhxkjsbfbkcjfbsjfficjjdjejf

3 0
3 years ago
2 H2(g) + O2(g) → 2 H2O(g)
alexgriva [62]

Answer:

77 L of water can be made.

Explanation:

Molar mass of O_{2} = 32 g/mol

So, 55 g of O_{2} = \frac{55}{32} mol of  O_{2} = 1.72 mol of  O_{2}

As hydrogen is present in excess amount therefore  O_{2} is the limiting reagent.

According to balanced equation, 1 mol of  O_{2} produces 2 mol of H_{2}O.

So, 1.72 mol of O_{2} produce (2\times 1.72) mol of H_{2}O or 3.44 mol of H_{2}O.

Let's assume H_{2}O gas behaves ideally at STP.

Then, P_{H_{2}O}.V_{H_{2}O}=n_{H_{2}O}.R.T   , where P, V, n, R and T represents pressure, volume, no. of moles, gas constant and temperature in kelvin scale respectively.

At STP, pressure is 1 atm and T is 273 K.

Here, n_{H_{2}O} = 3.44 mol and R = 0.0821 L.atm/(mol.K)

So, (1atm)\times V_{H_{2}O}=(3.44mol)\times (0.0821L.atm.mol^{-1}.K^{-1})\times (273K)

  \Rightarrow  V_{H_{2}O}=77L

Option (b) is correct.

5 0
3 years ago
What is the pH of the solution in which the [H+] is 1.0 × 10–4 mol/L ?
ddd [48]
PH is a simplified observation of the acidity of a solution, defined as the -log [H+] (negative logarithm of the hydrogen concentration).

-log[10^-4] = 4

The pH of this solution is 4.
5 0
3 years ago
Which of the following reagents is/are likely to be used to form the Britton–Robinson buffer solution used in the experiment?
Ierofanga [76]

Answer:

I. A polyprotic, weak acid

II. Na2HPO4

Explanation:

Buffer solutions are those that, upon the addition of an acid or base, are capable of reacting by opposing the part of the basic or acid component to keep the pH fixed.

Buffers consist of hydrolytically active salts that dissolve in water. The ions of these salts are combined with acids and alkalis. These hydrolytically active salts are the products that result from the reaction between weak acids and strong alkalis such as calcium carbonate (from carbonic acid and calcium hydroxide) or between strong acids and weak alkalis such as ammonium chloride (a from hydrochloric acid and ammonium hydroxide).

A buffer acid reacts when a weak acid or weak base is combined with its corresponding hydrolytic salt in a water solution, a buffer system called a buffer is formed. As in this case a weak polyrotic acid with Na2HPO4, which allows the solution to be maintained at a pH of 3.8 against small aggregate amounts of both acid and base, thus favoring the reaction at a pH of 3.8

A buffer system is not always appropriate, because the ions of some hydrolytic salts can, for example, damage organisms that come into contact with it.

4 0
3 years ago
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