The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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Answer:
(3,2)
Step-by-step explanation:
y = 4x – 10
y = 2
Substitute the second equation into the first
2 = 4x-10
Add 10 to each side
2+10 = 4x-10+10
12 = 4x
Divide each side by 4
12/4 =4x/4
3 = x
The solution is
(3,2)
5,595,756,198,388
Step-by-step explanation:
Answer:
8 and 9
Step-by-step explanation:
