Question

An open organ pipe is 2.46 m long, and the speed of the air in the pipe is 345 m/s.

Answer 1

Answer:

Fundamental frequency is 70.12 m

Explanation:

For an open organ pipe, the fundamental frequency is given by :

$f=\dfrac{nv}{2l}$

n = 1 for fundamental frequency

v is speed of sound in air, v = 345 m/s

l is length of open organ pipe, l = 2.46 m

Substituting values in above formula. So,

$f=\dfrac{1\times 345}{2\times 2.46}\\\\f=70.12\ Hz$

So, the fundamental frequency of this pipe is 70.12 m.