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Kamila [148]
1 year ago
14

Our milky way galaxy is 100000 lyly in diameter. a spaceship crossing the galaxy measures the galaxy's diameter to be a mere 1.

0 lyly. what is the speed of the spaceship relative to the galaxy?
Physics
1 answer:
Sidana [21]1 year ago
5 0

The speed of the spaceship relative to the galaxy is 0.99999995c.

A light-year measures distance rather than time (as the name might imply). A light-year is a distance a light beam travels in one year on Earth, which is roughly 6 trillion miles (9.7 trillion kilometers). One light-year equals 5,878,625,370,000 miles. Light moves at a speed of 670,616,629 mph (1,079,252,849 km/h) in a vacuum.We multiply this speed by the number of hours in a year to calculate the distance of a light-year (8,766).

The Milky way galaxy is 100,000 light years in diameter.

The galaxy's diameter is a mere 1. 0 ly.

We know that ;

L = L_0 \sqrt{1-\frac{v^2}{c^2} }

L = 1 light year

L₀ = 100,000 light year

1 = 100,000 \sqrt{1-\frac{v^2}{c^2} }

1 = 100,000 \sqrt{1-\frac{v^2}{(3*10^8)^2} }

\frac{1}{100,000}  = \sqrt{1-\frac{v^2}{c^2} }

v = 0.999999995 c

Therefore, the speed of the spaceship relative to the galaxy is 0.99999995c.

Learn more about a light year here:

brainly.com/question/17423632

#SPJ4

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A cat jumps from 2.5-meter-tall bookshelf to a 1.3-meter-tall countertop. If the cat
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<h3 /><h3>Potential Energy:</h3>

This is the energy due to the position of a body. The S.I unit is Joules (J)

The formula for change in potential energy.

<h3 /><h3>Formula:</h3>
  • ΔP.E = mg(H-h).............. Equation 1

<h3>Where:</h3>
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  • H = First height
  • h = second height.

From the question,

<h3>Given:</h3>
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Substitute these values into equation 1

  • ΔP.E = 15×9.8(2.5-1.3)
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  • ΔP.E = 176.4 J.

Hence, The change in Potential energy of the cat is 176.4 J

Learn more about Potential energy here: brainly.com/question/1242059

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A kite is 100m above the ground. if there are 200m of string out what is the angle between the string and the horizontal? (assum
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Let the angle between the string and the horizontal be theta.

Now  sin (Theta) = opposite side/hypotenuse

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Therefore Theta = Sin ⁻¹ ( 1/2 )

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b) 
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