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Natasha2012 [34]

3 years ago

8

A textbook is pushed across a desk. It experiences what type of force

1 answer:

In-s [12.5K]3 years ago

3 0

Answer:

kinetic friction force

Explanation:

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What are the two key elements needed for fossilization

xenn [34]

Body Fossils and Trace Fossils.

Hope I helped and good luck with school. Bye!

3 0

4 years ago

The sound from a loud speaker has an intensity level of 80 db at a distance of 2.0m. Consider the speaker to be a point source,

Tamiku [17]

Answer:

2.83m

Explanation:

The information that we have is

Intensity at 2.0 m: $I=80dB$ and $r_{1}=2m$

we need an intensity level of: $I_{2}=40dB$

thus, we are looking for the distance $r_{2}$ .

which we can find with the law for intensity and distance:

$(\frac{r_{2}}{r_{1}} )^2=\frac{I_{1}}{I_{2}}$

we solve for $r_{2}$ :

$\frac{r_{2}}{r_{1}}=\sqrt{\frac{I_{1}}{I_{2}} }\\\\r_{2}=r_{1}\sqrt{\frac{I_{1}}{I_{2}} }$

and we substitute the known values:

$r_{2}=(2m)\sqrt{\frac{80dB}{40dB} }\\\\r_{2}=(2m)\sqrt{2}\\ r_{2}=2.83m$

at a distance of 2.83m the intensity level is 40dB

5 0

3 years ago

Which action would be most likely to reduce the noise level of people talking in a restaurant?

vazorg [7]

B.adding carpet and fabric wall covering to absorb sound

7 0

2 years ago

Read 2 more answers

A circuit having a resistance, an inductance, and a capacitance in series is connected to a 110- v ac line.for the circuit R = 0

ludmilkaskok [199]

Part A)

Impedance of the circuit is given by

$z = \sqrt{(x_L - x_c)^2 + R^2}$

$z = \sqrt{(28 - 16)^2 + 0^2}$

$z = 12 ohm$

Part b)

Now in order to find the current we will use ohm's law

$V = i*z$

$110 = i * 12$

$i = 9.17 A$

Part c)

Phase angle is defined as

$\phi = tan^{-1}\frac{x_L - x_C}{R}$

$\phi = tan^{-1}\frac{12}{0}$

$\phi = 90 degree$

Part d)

now power factor is defined as

$cos\phi = \frac{R}{Z}$

$Power factor = 0$

6 0

4 years ago

Two tiny conducting spheres are identical and carry charges of -20μC and +50μC. They are separeted by a distance of 2.50cm. (a)

Dahasolnce [82]

Answer:

$14400\ \text{N}$ , Attractive

$3240\ \text{N}$ , Repulsive

Explanation:

$q_1$ = -20 μC

$q_2$ = 50 μC

r = Distance between the charges = 2.5 cm

k = Coulomb constant = $9\times 10^9\ \text{Nm}^2/\text{C}^2$

Electrical force is given by

$F=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=\dfrac{9\times 10^9\times (-20\times 10^{-6})\times (50\times 10^{-6})}{(2.5\times10^{-2})^2}\\\Rightarrow F=-14400\ \text{N}$

The magnitude of force each sphere will experience is $14400\ \text{N}$

Since the charges have opposite charges they will attract each other.

Now the charges are brought into contact with each other so the resultant charge will be

$q=\dfrac{q_1+q_2}{2}\\\Rightarrow q=\dfrac{-20+50}{2}\\\Rightarrow q=15\ \mu\text{C}$

$F=\dfrac{kq^2}{r^2}\\\Rightarrow F=\dfrac{9\times 10^9\times (15\times 10^{-6})^2}{(2.5\times 10^{-2})^2}\\\Rightarrow F=3240\ \text{N}$

The magntude of the force the spheres experience will be $3240\ \text{N}$

The spheres have the same charge now so they will repel each other.

7 0

3 years ago