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3 years ago

What did johannes kepler contribute to the study of planets

Physics

2 answers:

kondaur [170]3 years ago

6 0

He collected detailed data that led to the proposal of the heliocentric model.

Nana76 [90]3 years ago

4 0

Johannes Kepler was a main stargazer of the Scientific Revolution known for detailing the Laws of Planetary Motion. A stargazer, obviously, is a man who contemplates the sun, stars, planets and different parts of room. Kepler was German and lived in the vicinity of 1571 and 1630.
Despite the fact that Kepler is best known for characterizing laws in regards to planetary movement, he made a few other striking commitments to science. He was the first to discover that refraction drives vision in the eye and that utilizing two eyes empowers profundity recognition.

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A certain piece of metal (density 9.45 grams per cubic centimeter) has the shape of a hockey puck with a diameter of 13 cm and a

atroni [7]

Answer:

0.0195 m

Explanation:

$\rho _{p}$ = density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³

$d_{p}$ = diameter of hockey puck = 13 cm = 0.13 m

$h_{p}$ = height of hockey puck = 2.8 cm = 0.028 m

$\rho _{m}$ = density of mercury = 13.6 gcm⁻³ = 13600 kgm³

$d$ = depth of puck below surface of mercury

According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck

Weight of mercury displaced = Weight of puck

$\rho _{m} (0.25)(\pi d_{p}^{2} d ) g = \rho _{p} (0.25)(\pi d_{p}^{2} h_{p} ) g\\\rho _{m} ( d ) = \rho _{p} ( h_{p} )\\(13600) d = (9450) (0.028)\\d = 0.0195 m$

7 0

3 years ago

1 example of Deionization

xxTIMURxx [149]

Answer:

For example, the rain water does not have any salinity, except the small quantity due to the atmosphere, while the sea water has a very high salinity.

hope this helps you friend

7 0

3 years ago

A car speeds up as it rolls down a hill. Which is this an example of? A. positive acceleration B. negative acceleration C. relat

alina1380 [7]

I believe it is A. positive acceleration since it is speeding up

4 0

3 years ago

Q|C (a) You need a 45-ω resistor, but the stockroom has only 20-ω and 50-ω resistors. How can the desired resistance be achieved

NNADVOKAT [17]

In order to achieve the desired resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with the 20 Ohms resistors.
In order to get a 35 Ohms resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with two 20 Ohms resistors that are connected in parallel.

<h3>How to achieve the desired resistance under these circumstances?</h3>

In order to achieve the desired resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with the 20 Ohms resistors.

Mathematically, the total equivalence resistance of two resistors that are connected in parallel is given by:

1/Rt = 1/R₁ + 1/R₂

1/Rt = 1/50 + 1/50

1/Rt = 2/50

1/Rt = 1/25

Rt = 25 Ohms.

Next, we would connect this 25 Ohms resistor in series with the 20 Ohms resistor:

R₃ = 20 + Rt

R₃ = 20 + 25

R₃ = 45 Ohms.

In order to get a 35 Ohms resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with two 20 Ohms resistors that are connected in parallel.

1/Rt = 1/R₁ + 1/R₂

1/Rt = 1/50 + 1/50

1/Rt = 2/50

1/Rt = 1/25

Rt = 25 Ohms.

1/R't = 1/R₁ + 1/R₂

1/R't = 1/20 + 1/20

1/R't = 2/20

1/R't = 1/10

R't = 10 Ohms.

Next, we would connect the 25 Ohms resistor in series with the 10 Ohms resistor:

R₃ = 10 + Rt

R₃ = 10 + 25

R₃ = 35 Ohms.

Read more on resistors in parallel here: brainly.com/question/15121871

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Complete Question:

You need a 45-ω resistor, but the stockroom has only 20-ω and 50-ω resistors.

(a) How can the desired resistance be achieved under these circumstances?

(b) What can you do if you need a 35-ω resistor?

3 0

2 years ago

An inclined plane makes an angle of 30.0º with the horizontal.

Wittaler [7]

The force required to push the box upward is 145.3N and the force to pus the box downward is -109.3N

Data given;

mass = 15kg
angle = 30 degree
acceleration = 1.2 m/s^2
acceleration due to gravity = 9.8 m/s^2

<h3>Force against gravity</h3>

To move the plane upward, the box will move against gravity.

$F = F - mgcos X\\
ma = F - mg cosX$

Let's solve for F

$ma = F - mgcosX\\
15*1.2 = F - 15*9.8 * cos 30\\
18 = F - 127.30\\
F = 18 + 127.30\\
F = 145.3N$

<h3>Force towards gravity</h3>

When the force pushes the box down the inclined plane, it moves towards gravity.

$F = F + mgcosX\\
ma = F + mgcosX\\
15*1.2 = F + 15*9.8*cos30\\
F = -109.3N$

The force required to push the box upward is 145.3N and the force required to push the box downward is -109.3N

Learn more on force across an inclined plane here;

brainly.com/question/11888124

4 0

3 years ago